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If this is a one time search, and you're going to throw the code away:

grep "Dec 4 11:[0-1][0-5]" filename

The problem with your script is you are reading messages file again from top without ignoring what has been read previously.

You can use the below solution.


while true
do
if [ ! -f...

There are thousands of examples of code on this site that searches a file and performs some pattern matching. If you search the site, you will find plenty of examples.

-F '%' - this defines % as the primary field separator.

split($1, a, " ") - using field $1 (field #1 ) create an array that is split up using space(s) as the separator, creating subfields out of...

This is a VERY VALUABLE suggestion which relevance can't be overestimated. The "number 1 cron problem" is like this:

i have written script x and it works fine from the command line and after i put...

Firstly. There is never ever a reason to use "for" when dealing with an open-ended list.
Secondly. Convoluted one-liners should be formatted scripts.




This "while" construct easier to read...

Hope you know all vi editor options.
From command prompt do,
vi scriptname
then insert
#!/bin/bash
as first line followed by anything u want to do.
Save it and run it.

tail messages | tr -s " " | cut -d" " -f4,9-

Right. I've put Perl line in wrong place. This should work (also notice the added "\n"):for messages in `cat syslog_message_list.txt`
do
grep $messages syslog.`date +%d%m%y`.log | awk '{print $4 "...

Can you put code tags round the sample. I bet that there are two spaces between "Oct 6".
If this is the case you can generate a matching date like this.

DDMMM="`date '+%b %e'`" #...