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You've fallen into the same trap as in your other thread (https://www.unix.com/shell-programming-and-scripting/272879-how-get-value-file-serach-value-filename-dir.html). Don Cragun pointed the syntax...

From what you have said, presumably /home/$chat expands to the home directory for the user named by the expansion of $chat (/home/ram, /home/suresh, and /home/John, respectively for the three lines...

OK. Have you tried the code I posted? It reads line by line without any need for grep or ed.

Unless you have an unusual version of ls, that output is impossible.
Anyway we now know that "yahoo" is a directory and that there is probably only one script and that it probably does not vary its...

Off topic: The $PATH environment variable is reserved for the Shell. Choose another name for your environment variable ... $SEARCH ?

If you overwrite $PATH in the manner of your script, the Shell...

$! holds the PID of the last background process that was executed

Nice one...but to make it work on all flavors of unix the paste command needs to be "paste -sd: -" as legacy unixes dont understand stdin without the - placeholder.

using "sed -i" would alter the inode of the file.
using an "ed -s" instead would avoid this drawback.

printf "1d\nw\nq\n" | ed -s yourfile

#!/bin/bash

i=0
while read -r LINE
do
((i++))
echo "$LINE"
if [ "$i" -eq 3 ];then
echo ""
i=0
fi
done < "file"

awk -F "|" 'NR==1 {print $1}' test

Use nawk or /usr/xpg4/bin/awk on solaris.

# cat infile
dsd|dfsd|Sdfsdf|sdff
sdfwert|5rygrd|trhyr|dsfsd
edfgsd|aserhtrh|hjfg|


# sed -n '1s/^\([a-z]*\)|.*/\1/p' infile
dsd

You can omit the print statement, because it is the default action.

awk 'NR!=2 && NR!=6' txt1

I tend to use the print statement anyway because of readability.