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7,411
Posted By ygemici
* First of all let look the below # echo...
* First of all let look the below

# echo \h\h\h\h
hhhh

\ --> does no effect to echo ;)


* Anyway


# echo \++
++


first \ char is meaningless in here and echo after \ chars...
7,411
Posted By ygemici
because one backslah is not important in csh ;) ...
because one backslah is not important in csh ;)
needed X2 :)

both of '\' and 'n' escape its special means
then
\\ --> \
\\ --> n

5 backslah also same state ( last of \ like newline...
2,777
Posted By cfajohnson
The shell has already tokenized the command line...
The shell has already tokenized the command line and performed any redirection before the variable is expanded.

When you use eval, the expansion is done first, then the shell parses the result.
4,837
Posted By cfajohnson
It is for using the output of one command in...
It is for using the output of one command in another command, frequently to populate a variable:

output=$( $1 )


The ouput of the command in $1 will be stored in the variable $output.
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