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seq 0 50 61000 | sed 's/$/ 0/'

You are right. I thought awk would still try to read stdin, but apparently it does not when there is a BEGIN section and no other section. Interesting.

Corona688, that is not necessary since the action is inside the BEGIN rule.

I suggest a slight change:

awk '
BEGIN {
i = 0
while ( i <= 61000 )
{
print i, 0
i += 50
}
} ' /dev/null ...so it doesn't...

awk '
BEGIN {
i = 0
while ( i <= 61000 )
{
print i, 0
i += 50
}
} '

Slight variation:
awk '{split($0,A); getline<f; print A[1], A[2]-$2, A[5]-$3}' f=fileB fileA

Hi.

Similar to awk, Gary Perlman's |stat dm:
#!/usr/bin/env bash

# @(#) s1 Demonstrate column content arithmetic, |stat dm.
# See: http://hcibib.org/perlman/stat/index.html

# Utility...

Using paste & awk:-
paste file_A file_B | awk ' { printf "%d %d %d\n", $1, ($2-$7), ($5-$8); } '

Please post a representative sample of the input and the corresponding expected output.

Without any samples, try this:
awk '{a1=$1;a2=$2;a5=$5;getline<"fileB";print a1,(a2-$2),(a5-$3)}' fileA