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have you tried my command?
i used NR, at the end, the NR indicates: how many lines in your file.

if you apply the command on a different file, it works as well, for example:

echo "1 32 ...

using (n)awk:


# nawk 'NR==FNR{x[$1]=$2;next}{print x[$1]}' map infile
2
45
2
56
98
6598
98
56
56
98
98


HTH

With one awk command:
awk 'NR==FNR{sum+=$3;next}{print $3 "/" sum " = " $3/sum}' OFS="\t" FILE1 FILE1

Try this,
awk 'NR==FNR{a[$0]++;next} a[$0]{b[$0]=b[$0]+1} END {for(j in b) {print "count of ",j,":",b[j]}}' temp_uniq.txt temp.txt

The following approach works by manipulating the comma-delimited string into valid brace expansion syntax.

#!/bin/ksh

while read seq; do
while [ "${seq//[!,]}" ]; do
echo...

awk -F, '{for(i=1;i<NF;i++){for(j=i+1;j<=NF;j++) x=(x?x" ":y)$i","$j;print x;x=y}}' infileUse nawk instead of awk if on SunOS or Solaris :

# cat tst
12,23,45,1,2,3,5,54,8,4,1,65,6,6
1,2,3,4,5...

How about this,
awk -F, '{for(i=1;i<=NF;i++) {for(k=i+1;k<=NF;k++){printf " " $i FS $k}printf "\n"}}' inputfile

You can also calculate the decimal equivalent of an IP4 address using shell bit arithmetic. For example

#!/bin/ksh93

[[ $# != 1 ]] && {
echo "Usage: $0 ipaddress"
exit 1
}
...

Try...$ echo "172.16.112.100"|awk -F '\\.' '{printf "%d\n", ($1 * 2^24) + ($2 * 2^16) + ($3 * 2^8) + $4}'
2886758500

try this,"file" is the input file
sed 's/\(.\)/\1 /g' file | awk '{a=$1||$3;b=$2||$4;printf "%d%d(binary)=%d(decimal)\n",a,b,a*2+b}'

awk -F: '{printf "%10d\n", $1 * 3600000 + $2 * 60000 + $3*1000}' "$file"

Since you appear to be dealing with only seconds and milliseconds:

awk -F: '{print $3*1000}' infile

Another approach:
while IFS= read string
do
echo ${string##*:}
done < file

cut -d: -f2 file

perl -ne 'print if(s/:+/$&/g <= 6)' input_file > Output_file

awk -F":" 'NF-1<7' input_file

Not pretty but works:

$> cat infile
111
222
3:3:3::3:
4
5: 5: delete me!: 5:5:5:555
this one up::
:66:6:666:6:6
7:::7 delete me too!::7::7:: : 7:
get me up!
$> sed...

perl -ne 'print if(s/:/:/g <= 6)' input_file > Output_file