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One way (at the top of the script).

if [ $# -eq 0 ]
then
echo "please enter an option; -a for today, and -b for yesterday"
exit
fi

If I understood it right (I added 3 exclamation marks to represent 2 fields for easier spotting):

$> cat infile
one two three
one
two
three
four five six
four
five
six !!!
seven eight...

use '\b' to match the end of the number ,


[0-9]+0\b

If I got you correctly,Try:

awk 'NF>2 { print $1" "$2; $1=$2=""; print; }' file

Hi.

You could use a for-loop:


for( i = 3; i <= NF; i++ ) ...
Or, perhaps:

$ echo 1 2 3 4 5 6 | awk '{if( NF > 2) { $3 = RS $3}}1'
1 2
3 4 5 6

awk 'NF > 2 {
for (i = 0; ++i <= NF;)
printf "%s", ($i (i == 2 ? RS : FS))
print x
}' infile

or:

awk 'NR==FNR {for (i=2;i<=NF;i+=2) a[$1 FS $i]=$(i+1) ;next}
{printf $1 FS} {for (i=($3*10);i>=($2*10);i--) printf i/10 FS a[$1 FS i/10] FS}{printf "\n"}' File2 File1

Usually you use shell scripting to invoke external commands. awk is such an external command. It's quite powerful tool for text processing. When I tell you to use gawk, nawk etc, I'm just saying not...

perl -nle'
/(?:abc|def)/ and print join " ", /(?:abc|def)[\w-]+/g
or print
' infile