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It's not about order of evaluation, it's about your filenames being mangled from passing them through a pointless pipe chain then cramming them into read -d "\0". The -d "\0" is especially pointless...

Actually, how about this?

grep -Hc "dn: " /localbackup/ldap/* Will output file1:count
file2:count
fle3:count
... All in one efficient command.

I'm afraid I don't understand the problem, except that your code is utmost cumbersome. Why do you use the read -a at all? Why the complicated "command substitution"? The -rlt options to ls?...

I just encountered this behavior yesterday. ls on Linux now injects single quotes around filenames with spaces in them, for your convenience! Ugh! Eval or xargs would swallow those, anything else...

In bash you could have process substitution manage a named pipe for you. Below I duplicate this with exec onto file descriptor 7.

You can then simply read and discard from this file descriptor...

#!/bin/bash
program > program.log 2>&1 &
pid=$!
for s in {1..15}
do
sleep 1
done
kill $pid

You have another error: closure of first if is after last else and not before:
Your code corrected:
#include <stdio.h>

main() {

int c, i, state, wl;
int maxlength[15];

...

You are getting into the if(c == '\n') section with state as still OUT and thereby bypassing your ++maxlength[wl].

I don't think state serves any function at all though. You could dispose of it...

Hi,
Already, you have typo:
else if (state == IN) {
state == OUT;
++maxlength[wl];
wl = 0;
Regards.

No, there is always one more fields than delimiters.
Between consecutive delimiters there is an empty field.

As a side note, if you want to know the mac assigned to an interface, in a Linux system just read it from /sys:
cat /sys/class/net/eth0/address
Much faster.

Yes, with cut every occurrence of the delimiter separates a field.


--
The default delimiter in awk does not. Try:
ifconfig eth0 | awk '/HWaddr/{print $5}'

The correct syntax with test expr and [ expr ] for expressions performing numeric comparisons is -lt, -le, -eq, -ne, -gt, or -ge and for string comparisons is = and !=.

With [[ expr ]], the...

It isn't immediately obvious to me why bash complains about your provided code. (But, I usually use ksh instead of bash.) A recent ksh runs it without complaining.

Both bash and ksh are happy...

Yes, it assigns the string 'Stuff' to variable 'Var'.
Wether 'Var' contains a string "Stuff" or the filename (also a string) "Stuff" is no diffrence at all.

It neither points to the file, nor...