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Even this could do the trick:-#!/bin/bash

while read full_filename
do
directory="${full_filename%/*}/"
filenames="*.${full_filename##*.}"
echo "${directory}${filenames}"
done <...

Try
find /abc | awk '{sub (/[^\/]*\./, "*."); T[$0]} END {for (t in T) print t}'
/abc/b/*.gz
/abc/b/*.txt
/abc/a/*.txt

find /abc -type f -printf "%h %f\n" | awk '
{
EX = $2
sub ( /[^.]*[.]/, X, EX )
A[$1 FS EX]
}
END {
for...

Try something like this to start with. If you find problems, show us what you did to fix them. First. Before saying 'this does not work':

find /abc -type d |
while read dir
do
ls -1...

Try this first to check for the right files

find /tmp -user abcuser



And if you see the files are all correct and are the ones you want to delete, try this

find /tmp -user abcuser -exec...

You can try:#!/bin/sh
/script2.sh &
WAIT_PID=$!
# do other stuff
wait $WAIT_PID

This is typically done like this:
content of script1:

/path/to/script2.sh & # execute script2 in the background
other_commands
more_commands
wait # wait for all background...

when=$(( $when + $fifty_days ))
# change to
when=$(( $when - $fifty_days ))

That is a minus sign.

Also changed the original post to reflect the change.

try this: note it uses ksh - if you use bash uncomment the red code; comment the blue code and change the shebang to /bin/bash

#!/bin/ksh
#
# assumptions - the LAST friday means:
# Find...

I wrote this ultimate time tool for all those shell scripts wanting to do time stuff - parsing, clock, offsets and formatted output. Complex questions might mean you call it more than once or in a...

What shell do you use? Do you want a script that'd list these certain files, or a function you'd use from the command line?

Not surprising. With a numeric string 201206000000, the value being compared is 201206000000. With the string C201206000000, awk sees a variable name and since the variable hasn't been set, the...

You don't need the int() for this comparison, and it will hurt you if you're not using an awk that uses 64-bit ints. Just use:

ls abc.* | awk -F'.' '$2>'201206000000' {print $0}'

You say that the file naming convention is

but the example looks a lot more like the convention is

I can't tell which it is from the data you supplied.
It is good that the convention uses YYYY...

Think this should do you:

$ awk -F'.' 'int($2)>'201206000000' {print $0}' test.sh
abc.201206015423.txt
abc.201207013456.txt