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Here is one way of doing it:
awk '
/^[ ]*\/\*/ {
if ( NR > 1 && !(f) )
print "No_Condition"
f = 0
printf ( "%s =...

-n option to ssh will avoid this.


while read a b
do
ssh -qn $a uname -a
done < inputfile

You can overwrite the same line every time by printing a carriage return instead of a newline, the cursor will return to the beginning of the line but not travel down to the next line.

Note this...

Not sure what you want to achieve; if you want to output to a single line only, try adding a <carriage return> character:$ for i in {1..10}; do echo -en "\rCurrent Record = $i"; sleep 1; done

Try: ..);$1=$1;print

In the first two lines there are no commas in the last field, so no substitution takes place and the field does not get modified and therefore the record does not get...

Since India does not waste time with daylight saving time shifts, just setting TZ=IST-5:30 will give you the correct time in India at any time of year. For example, a few seconds ago:
TZ=GMT0...

Despite what DGPickett said, perl had no affect on the description of regular expression in the POSIX standards.

There are several variations on RE processing, but there are three main types...

Some flavors of regex have + for one or more, but you can just say 'ee*'. Also, there is '\{1,99\}' for 1 to 99 in the sed flavor. There must be about a dozen regex flavors, especially after the PERL...

awk 'NR>x+y{print A[NR%y]} {A[NR%y]=$0}' x=6 y=2 infile

In addition to the possibilities already listed, note that the standards only define the behavior of sed when the input is a text file. The output from the tr command is not a text file (by...

Based exactly on your input file, it works for me. What is not working about it for you?


$ tr -s '\n' ',' < file | sed 's/,$//'
alpha,beta,gamma

(no need for cat, though)

You can also...

$value=(split(/:/,$req_user_info))[3];

Hi
You should use it like this:

my ($req_user_info)=grep(/$x/,@input);

This is because grep returns a list, and when used in scalar context, you get the length.

Guru.

Yes, && FNR>1 keeps the value on the first line of the file from being printed. You can leave that out if the actual file does not contain a header...

It's trying to ask for a password and can't, since you have no terminal. The way to fix that is to remove the password requirement for that sudo entry, not remove the TTY requirement.

Be very...

From a syntax point of view, it should be something like this:

30 17 8-14 * * [ `date +\%u` -eq 6 ] && /rebootscript # to reboot every second saturday
30 17 22-28 * * [ `date +\%u` -eq 6 ] &&...

Try:
/usr/xpg4/bin/grep -E '^May 29 15:([01]|2[0-3])' /var/adm/messages

try this ;)
/usr/xpg4/bin/grep -E 'May 29 15:([01][0-9]|[2][0-3]):[0-9]'

Try with

/usr/xpg4/bin/egrep

Did you try mine with that input? It will work.

---------- Post updated at 07:26 AM ---------- Previous update was at 07:20 AM ----------

/^uid=[0-9]*(\([^)]*\)).*groups=.*(macusr).*/

is...

firstly you match pattern and print that line. you set a counter to 6, so then each line after you evaluate c-- (decrease by 1) and then test if it's above 0. using the semicolon here you omit the...

Hi,

Try this one,


nawk 'BEGIN{FS="=";}/Server.Host/{sub ($2,"test.sol.box");}1' test.txt


Here 1 in the end of the block will display all the lines.

FS must be specified in BEGIN...

$ cat -n a.txt
1 one
2 two
3 three
4 four
5 five
6 six
7 seven
8 eight
9 nine
10 ten
11 eleven
$ awk...

Wonder what you mean by "their info"?

If it's just the login name:
logins -g tiadm | awk '{print $1}'If it's everything available and in a machine-readable format:
logins -xtog tiadm

One awk:
awk -F: 'NR==FNR && $1==g{split($4,T,","); for(i in T) U[T[i]]; next} $1 in U' g=tiadm /etc/group /etc/passwd