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Please use code tags as required by forum rules!

That depends on VAR1's contents. If created with "\n" separators, use double quotes when using (echoing) the variable.
If it just contains spaces,...

No need to delete the data.

If you are not using LVM, a simple newfs command will create filesystem, then you mount it and use it as you see fit.

If you are using LVM, simple do a pvcreate on...

sed 's#/.*##' file1
Skip lines without a /:
sed -n 's#/.*##p' file1

$(hostname) (which is the same as `hostname`) or $HOSTNAME could by tried as well.

hth

Hello aav1307,

Could you please try following and let me know if this helps.

touch file1-$(date +%Y-%m-%d_%H:%M:%S)_`hostname`


Thanks,
R. Singh

Did you consider searching these fora, or even look at the link at the bottom of this page?

Hello aav1307,

Following may help you in same.(Not tested though)
Code 1: Following one will check if number of fields are one or line is empty it will not print those lines.

awk '{if(NF==1 ||...

your request is not clear

if you want to delete completely empty lines, try sed
sed '/^\s*$/d' file


your example will work with

awk 'NF!=1' file

Hello aav1307,

Following may also help you in same.

cat file{1,2} > OUTPUT_file ##In Bash, ksh, zsh

OR

awk '1' file1 file2 > OUTPUT_file
OR
awk '1' file{1,2} > OUTPUT_file ##In...

appreciate the repeat - until!

Indeed the output was not exact, and one line was even left out.
Here is another fix:
while
read line2 <&4
e2=$?
read line1 <&3 || [ $e2 -eq 0 ]
do
if [ -z "$line1" ] && [ -n "$line2"...

Nice!

But - two lines are missing, the ones that would be first to be printed alone.

And, if you reverse the order of the files, you get 111 aaa
222 bbb
ddd
eee
fff

333 ggg
444 hhh...

Here is a general merge
#!/bin/sh
while
read line2 <&4
e2=$?
read line1 <&3 || [ $e2 -eq 0 ]
do
if [ -z "$line1" ]
then
while read line2 <&4 && [ -n "$line2" ]
do
printf...

What is ' file find pattern'?
1. a pattern in the file name
2. a pattern in the file's data

What is 'new file output'?
1. write to a new file
2. copy the file to a new location

Please give...

For something that can take any number of groups separated by blank lines in both files, your could try:
awk '
function print_rest() {
while(c1[g2] > c2)
printf("%s\t\n", d[g2, ++c2])...

try also:
awk '
FNR==1 {l=0}
! /./ {l=1; if (FNR!=NR) print; next}
FNR==NR { if (! l) { a[a1++]=$0; } else { b[b1++]=$0; } ; next }
{if (! l) {c=a[a2++]} else {c=b[b2++]}; print $0, c}
'...

Try this (an ad hoc quick and dirty solution for exactly your samples, no error checking etc.):awk '/^$/ {do {ST=getline S0 < F1; print S0} while ((ST==1) && S0!=""); next}
...

Confused. What exactly are you asking? It looks like you have resolved your own issue.

This is confusing. You're using both back ticks ` and $(). It's not a problem; however, given some syntax issues with your example, it's not clear. For example, what exactly is command1
...

try also:
awk 'NR>1' infile

sed 1d filex

obe way:

sed -n '2,$p' myFile

How about column -t file
data description importantainfo
121 desp1 info1
122 desp2 info21
2342 desp3 info32
5345 desp4 info43

you can play with the 'fmt' value to get where you want to be:

awk -v fmt='%-10s%-15s%-15s\n' '{printf fmt,$1,$2,$3}' myFile
---------- Post updated at 11:45 AM ---------- Previous update was...

akshay@Aix:/tmp$ pr -m -t -s' ' file1 file2
1 aaa bbb ccc
2 ddd eee fff
3 ggg hhh iii