Search Results

That is a tiny bit too simple. Since $2 expands to a string containing a non-numeric character (the percent sign), the comparison will be a string comparison instead of a numeric comparison. ...

An AWK version
awk '$2>80{print $1}' jeo_fb.file

A Perl version
perl -nale 'print $F[0] if $F[1]>80' jeo_fb.file

Hi,
Maybe :
awk '/ [8-9][0-9][.0-9]*%| 100[.0-9]*%/ && $0=$1' file

Regards.