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Why are you using {"/home/user1/bin/outfile.out"}
Just put filename alone without braces and ".

awk '{if( NR==1)print ">"FILENAME;else print}' S5_SK1.chr01

echo "0000000011179E0A" | sed 's/^0*//'

Try this.

awk '{arr[NR]=$1} END{if(NR%2==0)print arr[NR/2]; else print arr[(NR-1)/2]}' inputfile

awk '{arr[$1]+= $2}END{for (i in arr) print i" "arr[i]}' inputfile

If there are only two fields, this will work.

awk -F"|" '{print $2"|"$1}' filename

#!/bin/ksh
for i in `ls path`
do
mv $i $i.dat
done


path is the path where your files exist

grep <pattern> <file> | tail -200

This command will give you escaped * from your grep command. Then use it in the final sed command.
grep <pattern> <file> | sed 's/*/\\*/g'

Try this:

's/5 2 \* \* 2 root backupdat/5 5 * * 3 root backupdat/' /etc/crontab

sed -e 's/[\+][0-9 ]*/,&,/' -e 's/[a-z0-9_-.]*@[a-z0-9_-.]*/,&,/' inputfile

Replace #!/bin/csh with #!/bin/sh

echo "Enter the line number";read num; awk -v line=$num '{if($1==line){for(i=1;i<=NF;i++){if($i ~ /-bwout/)x=$(i+1);if($i ~ /-bwin/)y=$(i+1);}}} END{print y" "x;}' file


file will have the...

#!/bin/csh
set QUERY='netscape'
set COUNT_NETSCAPE=`ps | grep -c $QUERY`
echo $COUNT_NETSCAPE