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All 'segfault' means is that your program attempted to access a memory page that either
1) doesn't exist, or
2) your program doesn't have permissions to access.

There's almost endless reasons...

segfault is one kind of runtime error and there can be a number of reasons for it...the most common ones are buffer overruns or stepping into memory which is read only or dereferencing an invalid...

This loop never ends, you just walk right off the end of the string:

for(;s < (s + n/2);++s)

n is a constant value, you keep incrementing s, and off you go.

The relationship between fork and the number of processes created isnt 2^n but 2n...and in this program it will be 2n-2 due to...if (p>0) { fork();}

sed is the tool for this:

sed -e 's/<name>\(.*\)<\/name>/\1/g' -e 's/<description>\(.*\)<\/description>/\1/g' file.xml > newfile.txt

To mess with another process' memory in Linux you use ptrace (http://unix.stackexchange.com/questions/6301/how-do-i-read-from-proc-pid-mem-under-linux) as described here. This is the same way things...

Look at it this way. Is this group of 32 bits signed or unsigned?
11111111111111111111111100000000 by itself it's neither... Whether it's signed or not is wholly up to how you interpret it.
...

Where the variable is stored has nothing to do with how it does pointer math. I can't see your code from here, but I'd venture they were all on the stack, with nothing in the heap. What type it's...

You're not listening. This isn't the bad old days when drives came with defect lists. Drives these days handle their own defects and replace bad sectors with "spare" sectors when necessary, there's...

The internal representation of floating-point numbers is a well-documented standard (http://en.wikipedia.org/wiki/IEEE_754-2008).

As for why two things can represent identical numbers, it's...