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Add zero
$ printf "%+010.2f" "-23.435456"
-000023.44

Add plus to Devaraj's solution to get plus sign before positive numbers
$ a=9
$ printf "%+2.8f" $a
+9.00000000
$ a=-9.999
$ printf "%+2.8f" $a
-9.99900000

Try using print command with the right format.

$ echo $a
-000023.44
$ printf "%2.8f" $a
-23.44000000


cheers,
Devaraj Takhellambam

I have no idea what you're trying to do and the variable names don't make any sense to me, but the following is a reformatted, simplified version of your script that is a valid bash script (and is...

And the same rule applies here:
value=$(printf "%-$3s" "$2")value= is an assignment, no need for quotes.
$2 is an argument (of the printf command), to be quoted.

---------- Post updated at 12:37...

Try:
vorg_nr=$value
echo "$vorg_nr"

You do not need the double quotes with the assignment, but you do need them with the echo statement, otherwise the content of the variable will be interpreted...

Hi, try:
echo "$value"