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With GNU date, you can do something like this, in sh or bash:
#!/bin/sh

# Past date in seconds since Epoch
past=$(date +%s --date "12/02/2013 11:21")

# Now in seconds since Epoch
now=$(date...

Nothing fancy in the below script, just an all-in-one task:
awk '{$10=$7;$7=$8=$9="na"}
$10~/aa1/{$7="aa1"}
$10~/ab2/{$8="ab2"}
$10~/ac3/{$9="ac3"}
1' input_file > output_file

Try this one instead :
awk -F, '{A[$1 FS $2] = A[$1 FS $2] ? A[$1 FS $2] FS $NF : $N} END {for ( k in A ) print A[k]}' output/* > output-4.csv

Try also this awk code as well :awk 'NR==FNR{A[++i,1]=$1;A[i,2]=$2;A[i,3]=$3;next}
{j=0;while(j++<i)if(($2==A[j,1])&&($3>=A[j,2])&&($3<=A[j,3]))print}
' filterfile datafile

Edit - Nevermind, don't pay attention to this stupid question.


Is it acceptable to use a range file like this?

Actually, Scrutinizer's reply is way more simple to use :)
if ! $SERVICE status > /dev/null 2>&1uses exit status as well; in this case if $SERVICE status did not (!) exit with status 0; then rest of...

Thanks Corona688 for your input !
Here is another solution using AWK:
~/unix.com$ awk '{gsub("\r","");print > "file"$NF".txt"}' RAW

awk '{print > "file"$NF".txt"}' RAW

awk '{print > $3".txt"}' EDIT.txt

awk '{print > $NF".txt"}' RAW

Actual Debian Testing (Jessie) also uses gawk after a "standard system" install.
You still get mawk if you choose to not install the "Standard system" at Tasksel install step.

\r is added by your text editor (Windows text editor?) at the end of each line (carriage return (http://en.wikipedia.org/wiki/Carriage_return#Typewriters))
You have to configure it to NOT write \r...

Here is a solution using awk:~/unix.com$ awk 'int(100*rand())%5<1' file
5 and 1 are the parameters you want to modify here : 1/5 = 20% in this example

To be more specific in your...

Try this then (could not test my previous code 'cause I was on my smartphone)awk '!($0~x)' x="$3" file

It's not sed but you can try this:
~/unix.com$ awk '!A[$0]++' file

From your sample code, it's impossible to find CDR3 on second and fourth line (ID 1 & 3). Is there any [tab] and [spaces] mixed?

Try this
~/unix.com$ awk -F\| 'gsub(/ /,"|")&&$4=$4?$4:"NULL"{print $1,$4}' f
The above script is overcomplicated, use Corona688's or in2nix4life's suggestion instead :p

One way :
~/unix.com$ awk 'NR==FNR{A[$1]++;next}A[$1]==2' file.txt file.txt

Which shell are you using?

In sh, dash, should run on bash as well:
#!/bin/sh

if [ ! "$1" ]; then
TEXT="Data_0"
else
TEXT="$1"
fi

if [ ! "$2" ]; then
Lines=45
else
Lines=$2
fi

A bit straightforward, but it should do the trick, at least on the sample you provided:
~/unix.com$ awk -F'=' '/NAME/{n=$2}/TARGET/{t=$2}/STATE/{s=$2}{if(s&&t&&(s!=t)){s="";t="";print n}}' file...

#!/bin/bash
sum=0
for i in $@; do sum=$((sum+i)); done
echo $sum
exit 0~/unix.com$ bash script 4 5 6 7
22
See man bash (https://www.unix.com/man-page/All/1/bash/) for more infos

Another way:~/unix.com$ d='/root/logs/testing/today/'; echo ${d%/*/}
/root/logs/testing

Here is a start (it's #!/bin/sh, but it should run with bash too):#!/bin/sh

FS='|'
file=; while [ "$file" != 'done' ]; do
[ "$file" ] && files="$files$file$FS"
read -p 'What is the name of...

~/unix.com$ awk -v var='( |^)a:2( |$)' '$0~var{getline x;getline;print x RS $0}' file
a
b
~/unix.com$ grep -A2 '\( \|^\)a:2\( \|$\)' file
b:2 a:2
a
b

Here is it, but i'm still not sure about output file (my awk script below cat file2 to output (print>>"output")
the notmatched file contains the unmatched strings from file1
~/unix.com$ awk...

as in abcd 123 198 xyz1
In other words, each columns are separated by ' '(space)?
$1 in my script means the first field, as in abcd 123 198 xyz1, because I set FS to :

If anything else, sorry I...