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Yes, the code above should work. In this specific case (i.e., >0), you could further simplify the lines:
(CM > 0) && !CR ||
(CR > 0) && !CM ||
NR == 1
to:
CM && !CR ||
CR && !CM ||
NR == 1...

You mean ONE or more homo AND NO hetero or NO homo AND ONE or more hetero? Then, yes, that's how you do it.
I have to admit, using >= 2 (or, in your second case, 1 ) would make the logics way...

Please become accustomed to provide decent context info of your problem.
It is always helpful to support a request with system info like OS and shell, related environment (variables, options),...

One could also try:
sed 's,0/1[^[:space:]]*,homo,g
s,1/1[^[:space:]]*,hetero,g' file
If all of your fields are <tab> separated and some fields might contain <space>s, replace each occurrences of...

sed does not understand fields / columns without a lot of effort, awk can loop through them.

Loop starts at 6 for efficiency, if the 0/1 can come in any field change it to 1.

$ awk -F"\t" -v...

Your file shows what we suspected. It is a file that have been saved from a msdos operating system. It needs to be converted to Unix like format, first.

perl -nle 's/\r$//; /SF=(\d+)/; print if $1...

Sure, but any value greater than 400 would be always 3 digits (or more) and if the maximum number is 818 a three digit is sufficient.
A variation, if the maximum number could be arbitrary.
perl...

Yes. Look at the code and how it loops across fields 10 until end-of-line. Now imagine what were needed to make it loop across fields 1 to 9...

Assuming "letters" stands for "characters", and interpreting your desired output like "remove everything in a field after the first colon", and using <TAB> as the output field separator, would this...

Please also explain what you mean by "remove al letters after : character". The sample data you provided did not contain any letters in the fields you specified and instead of removing letters after...