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Please note that rveri only supplied a partial answer to the question about what code had been attempted by the submitter. Until that question is answered in full, please refrain from posting...

Maybe something like:
awk '
{ h[substr($1, 7, 1)]++
}
END { for(i in h)
printf("%s_hosts = %d\n", i, h[i])
}' file
producing the output:
d_hosts = 1
m_hosts = 8
o_hosts = 1
p_hosts = 17...

I'm pretty sure that's only a snippet from your attempt. Post it in its entirety.

What if that char is NOT p , d , o , or m ?

Please get rid of the old style call of the expr program
i=`expr $i + 1`
k=`expr $i + 1`
And use the shell-builtins instead
i=$((i+1))
k=$((k+1))
or
((i+=1))
((k+=1))
And please avoid...

My second sample
works the same as Scrutinizer's sample:
sort the file on the 1st field and pipe the result to awk or a while loop. The awk automatically loops over each input line, so the code...

Try:
sort -k1,1 -k2 datafile.txt | awk '$1!=s{s=$1; close(f); f=s ".out"} {print>f}'

if ( F )
s = s ? s OFS $i : $iif expression F is true, then concatenate string 's' with value of field 'i' preceded with the output field separator OFS (if s is not empty). If 's' is empty assign...

All of the proposals so far fail if there are other dots in the line, e.g. file name extensions or like. You need to isolate the row of timing dots like e.g.
awk '{sub(/^[^:]*::/, ""); print...

Just trying out different methods in case anyone is interested:

Perl:
perl -lne 'print $_ =~ tr/\.//' file
Python:
python -c 'print open("file").read().count(".")'

tr -Cd '.' < file | wc -c

It is not solved by above code. if you have several lines, you calculate wrong.

try this:
grep -o "\." infile|wc -l
awk '{sum+=gsub(/\./,"")}END{print sum}' infile

Another way with sed :
sed 's/\.\([^.]*\)$/ \1/' file
or
sed 's/\./ /7' file

you may try

$ cat test
tcp 0 0 10.80.110.100 2900 1 10.40.104.6.42769 ESTABLISHED
tcp 0 0 10.80.110.100 2900 1 10.40.103.7.38620 ESTABLISHED
tcp ...

Try:
UNIX95=1 ps -p "$PID" -o pcpu,pid,ppid,stime,etime,args
-edit- OK, I see CarloM already answered this one..

It's -p for proc list (which I assume was the aim).

Try ($2==pid1)

EDIT: Or, maybe, ($2 ~ "^"pid1"$") ?

I wrote a shells script that takes the output from stdin and surrounds it with #s.

Hope this helps.


#!/bin/bash
#
#

# read from stdin and dump to a temporary file...

Or
awk -F'[]] |[]]$' '{print $1 "]"}' file

GNU awk 4+:
awk '{ print $1 }' FPAT='[[][^]]+[]]' infileStandard awk:
awk 'match($0, /[[][^]]+[]]/) {
print substr($0, RSTART, RLENGTH)
}' infile
If you need all the occurrences:...

What about
awk '{gsub ("\] \[", "];["); print $1}' FS=";" file
[ Aug 19 21:02 apptime_flagECQAPP ]
[ Aug 24 01:43 apptime_flagECTAPP ]
[ Aug 28 01:47 apptime_flagMOWSQ101 ]
[ Aug 28 01:49...

but then you loose the brakets in the output hehe... yep messy...

awk is messy with [ ] characters. I'm on Solaris so awk/nawk is even messier

Try: tr piped into awk as a general approach. If this works with the ancient BSD /usr/bin/awk of Solaris it will ...

Try the awk below...
awk -F" ]" '{print $1 FS $2 FS $3}' file

depending on how picky your awk is:

awk -F'(\\[)|(\\])' '{print "[" $2 "]" }' myFile

See if that fits you.

awk '/PV Name/ {if (!a[$NF]++)print $NF}'