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In any event this is either going to be a memory hog, or require two passes thru a file. Neither is a great choice. I'm opting for two passes.

#!/bin/bash
cd /path/to/directory
ls grad*...

In your original problem, each entry in fit.txt contained 3 lines that contained the string +/- and the awk script I supplied plucked a value from each of these lines and added a new line after find...

With the sample provided, the following simple awk script seems to work:
awk -F' *=* +' '/[+]\/-/{printf "%s%s",$2,(++i%3)?" ":"\n"}' fit.txt
If you are using a Solaris/SunOS system, use...

Here's one possible way:

$cat temp.sh
sed -n "/^Final/,/^correlation/ p" infile > temp1.x # get segments
grep "^[a-z]_[0-9][0-9][0-9][0-9] " temp1.x > temp2.x # get lines
sed "s/.* = \([^ ][^...

For your test input, is this the first line of output you expect?
0.497897 0.00459204 1.57077

I see nothing resembling that output in your input so am confused to which lines you expect grep to match.

this should fix ur prob:

cat test.dat|awk '$NF~/^20.0)/{print}'

using awk:
cat test.dat|awk '$NF~/20.0)/{print}'

awk -F, ' { if(match($2,/20.0/)>0) print; } ' test.dat

If you want to grep 20 then why you need to sort...?



Which 20..?
assuming below from 8th column.

$ awk '$3 ~ /20/' file
1000 000008 (93.906141776920549, 90.0)

and

last column

$...

Did you try cat ?