Search Results

Sure:

awk '
NR==FNR{ # When the first file is being read (only then are FNR and NR equal)
A[$1]=$3 # create an (associative) element in array A...

An approach using join
join -t"|" -1 2 -2 1 -o 1.1 1.2 1.3 1.4 1.5 2.2 1.7 1.8 1.9 1.10 1.11 1.12 1.13 2.3 1.15 1.16 1.17 1.18 file2 file1

Small variation with two single arrays:
awk 'NR==FNR{A[$1]=$3; B[$1]=$2; next} $2 in A{$6=B[$2]; $14=A[$2]}1' FS=\| OFS=\| file1 file2

Hey,

Try sth like this,


awk -F'\|' 'FNR==NR{a[$1]= $2"^"$3;next;}a[$2]{split(a[$2],b,"^");$6=b[1];$14=b[2];}1' OFS="|" file1 file2


Cheers,
Ranga:)

Hi All,
I have two files in the following format.

File 1 :

1044|1|20121031|2910039.4|MR|201210|G1044|E
1082|2|20121031|1664662.84|MR|201210|G1082|E
1696|3|20121031|190801.5|MR|201210|G1696|E...

The regex does not match this data either.


$
$ cat f77
000800 15 test1 PIC X
000800 15 test1 PIC XX
000800 15 test1 PIC XXX
000800 15 test1 PIC X(8)
000800 15 test1 PIC X(12)
000800 15...

That regex does not match any of lines in the input file.

Hi,

Moving a text file just renames the text file - no conversion is happening.

You'll need to consult the tools available on your system - for example on most modern Linux systems you can use...

echo "ABC_HYND_JDHD_20130125120345.txt" | sed 's/[0-9]\{6\}\.txt/.txt/'
or
echo ${filename/[0-9][0-9][0-9][0-9][0-9][0-9].txt/.txt}

$ echo $filename | nawk -v OFS=_ -F_ '$NF=substr($NF,1,8)".txt"'
ABC_HYND_JDHD_20130125.txt

OK:

awk '
NR==FNR{ # while reading the first file
for(i=2; i<=NF; i++) A[$1,i]=$i # record every field and tie it to the value of the...

OK, have a try with pseudo-multidimensional arrays in awk:
awk 'NR==FNR{for(i=2; i<=NF; i++) A[$1,i]=$i; next} {for(i=2; i<=NF; i++) if($i=="") $i=A[$1,i]}1' FS=\| OFS=\| file1 file2

What have you tried so far, what was your idea?

$ nawk 'NR%3!=0{printf("%s ",substr($0,2,length))}NR%3==0{printf("%s\n",substr($0,2,length))}' input.txt
001 jkilo yrhfm 00056 jhdf rjhwjkrh +u8jk5h3 uru ehjk
002 jkfhk hfjkd 748395 fdjksfh...

Hi, if there is a match that involves:
group 1: the beginning of a line(^) or a field separator (\|), followed by
group 2: 1 or more numbers or dots, followed by
a dot(\.), followed by
group 3:...

See if this works:
perl -pe 's/(^|(?<=\|))([0-9.]+)\.(\||$)/$2$3/g' file

Try

perl -pe 's/\.\|/\|/g' file
100000||1925-01-10|00:00|1862SHERMA NAVE#1SE||EVTON|IL|60201||22509|BDSS|62007|2639|26670
100001||1935-01-10|00:00|1862NEW . YRK...

$ sed 's/ *|/|/g;s/| */|/g' file1.txt
1|a|4757634|jund jdkj|erhyj
2|a|4757634|jnd jdkj|rhje hjrhwj

Assuming that there are no tabs to be removed:
sed '/^ *$/d;s/ *| */|/g' file

I propose you a solution, maybe it is not the best one but you have to correct a bit of code but it works.


awk '$0 ~ /\(/, $0 ~ /PRIMARY/ {print $1,$2}' kk | while read var tipo
do ...

try

$ cat file
12345JackYKing32N
1235 JulyYoig 31N

$ awk -v var="5,4,1,4,2,1" '{n=split(var,P,",");k=1;for(i=1;i<=n;i++){s=s?s"|"substr($0,k,P[i]):substr($0,1,P[i]);k+=P[i]}print s;s=""}'...

sed 's!\(.\{5\}\)\(.\{4\}\)\(.\)\(.\{4\}\)\(.\{2\}\)\(.\)\(.*\)!\1|\2|\3|\4|\5|\6!g' infile

s=s?s","i:i # Here we assign values to s. First here it checks s presents or not

s? --> Is s present? If present then do the true part else do the false part. see below.

s?True:FalseAssume...

awk -F "|" '{ for(i=1;i<=NF;i++){if($i ~ /[0-9]\.[0-9]/){s=s?s","i:i}}print s;s=""}' file

This is my script. name is test.sh

$ cat test.sh
file=$1 #file name
FIR=$2 # first field to print
FILD=$3 # Number of fields

awk -v first="$FIR" -v Field="$FILD" -F "|" '{ s=$first;...