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The program executed by execl is the child.

The parent can read those values, yes. The child writes to the pipe, the parent reads. It's the same pipe even after fork() so they are connected by...

Your program will likely crash or malfunction, since argv[0] is traditionally the name of the program, and the argument after the last one you give execl must be null, so try this:

const char...

if ((PID1=fork())==0) { // child
close(fd[0]);
dup2(fd[1],STDOUT_FILENO)
close(fd[1]); // close ALL loose ends!
execl("~/Escritorio/SO/todos-P-Modulo2-Sesion4/esclavo","2","10"); ...

Yes, that's it. exec() replaces your current program. You have to fork, whether you want it in the foreground or not. Just wait() for processes to finish if they're in the "foreground".

There's...

You're not quitting in your child code, so they finish executing the child code then continue blithely on into the parent code. Since you haven't posted your complete code I can't tell what they'd...

Makes sense, yeah. It looks like hexdump squeezed some zeroes together though, where it put the *, got to watch for that.

You can write entire structures and such to file by the way, you don't...

Look closer.

#include <stdio.h>
int main(void)
{
int n=32;
fwrite(&n, 1, sizeof(n), stdout);
}

$ ./a.out > bin.bin
$ hexdump -C bin.bin
00000000 20 00 00 00 ...

Depends what's in it. Your integers are probably four bytes. "32\n" would be slightly smaller. Whereas binary is always the same size every time. hexdump -C filename

Well, to match, you need to lose the * in the definition, too.

Dynamic Memory - C++ Documentation (http://www.cplusplus.com/doc/tutorial/dynamic/)

However, now I see from your diagram, you...

The "(i%7==0)" is incorrect. It only works the first time i hits 7.

It should be( ( ( i + 1 ) % 8 ) == 0 )And not the parenthesis. I'm not sure about operator precedence between "+", "==", and...

space matter !
if [ "$opcion" = "p" ] <---good
if [ "$opcion"="p" ] <---badyou might want to use a case statement instead of if

case $1 in
p)
echo $1
echo "Escribe una cadena"
read cadena...

Perhaps something like this, and don't forget to run with $ . script_name

#!/bin/bash
trabajo=$1
numero=$(jobs | awk -F [][] "/$trabajo/"' {print $2; exit}')
if [ -z "$numero" ]
then
echo...

Jobs will only list jobs started by the current shell. As your scipt is run in it's own version of the shell it won't should jobs started by the parent shell. You man need to use ps to do this (or...

That is because jobs are local to the shell. When you run a script you are creating a child shell and in this child the list of jobs are not inherited from the parent.

Try sourcing your script-...

In this case, since the actual process name is hidden in a variable, I'd go with adding a second pipe to your statement like so:


pe -ef | grep -q $process | grep -v grep


The -v option...

We may have crossposted. Try "$@", quotes and all, that should expand to "$1" "$2" "$3" ...