Search Results

And in sed :
sed '/^#/{x;p;x;}' input-file

Hello Mudshark,

Could you please try following and let me know if this helps you.

awk '/^#/{print RS $0;next} 1' Input_file

Output will be as follows.

blah
blah #do not insert here
...

Ravinder, you worked around
gsub(/[^[:digit:]]/,X,Q)

Try alsoawk -F\| '{$7=$3; $8=""; gsub(/^[^0-9]*|[^0-9]*$/, "",$7)} $7' OFS=\| file
1|net|ABC Letr1|1530|||1|
1|net|EXP_1040 ABC|1121|||1040|
1|net|EXP_TG1224|1122|||1224|
1|net|RExp 123 456...

Hello Mudshark,

Following may help you in same.

awk -F"|" '{Q=$3;gsub(/[[:alpha:]]|[[:punct:]]/,X,Q);sub(/^[[:space:]]/,X,Q);sub(/[[:space:]]+$/,X,Q);$(NF)=Q;if(Q){print $0 OFS}}' OFS="|"...

print lines between <pattern1> and <pattern2>.

assuming pattren 1 is 'select'
pattern 2 is 'from'

a crude way of printing the lines between pattern1 & pattern2


v1=$(grep -n 'select' ...

Your problem in awk was that /sqry/ was looking for a line containing the literal string sqry not the string contained in the variable sqry. To do what you were trying to do in awk, you could have...

For reference, awk use of variables. There is no need to escape the double quote:
awk '$0~b,$0~e' b='select_id="x_0' e='from' infile


--
On Solaris, use /usr/xpg4/bin/awk

How about sed?


var='select_id="x_0' #you need not escape " when using single quote
sed "/$var/,/from/" x.txt

This change will not take effect for a user until that user changes his or her password. To force a user to change his or her password at next login, use the command:

passwd -f <user_name>

find /folder/* -prune -type f -name 'Rajini*'

This works for me on a Solaris system