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The Advanced Bash-Scripting Guide has some exercises (http://www.tldp.org/LDP/abs/html/exercises.html).

To execute the block, you need to have a slash / on a line of its own, after the END; line.

Try something like...$ string1='3X'

$ case $string1 in [0-9][0-9]) : ;; [0-9]?) string1=${string1:0:1} ;; esac

$ echo $string1
3

$

Try...$ cat file1
Tom|london
Tom|london
Tom|Paris
Adam|Madrid
Adam|NY
Tom|amsterdam
Tom|amsterdam
Tom|amsterdam
Tom|amsterdam

$ awk -F'|'...

You can just use sed....sed '/PATTERN/s/ to be changed/, YEHA! to be changed/' FILENAME

I thought that file ownership is just a user ID number, which you can see using ls -ln

See... https://www.unix.com/302098992-post2.html

Oh I see the problem. $1 and $2 are local to functions but you are not passing parameters to the function. Perhaps define a and b outside of the functions, e.g...$ cat sh.1
menu ()
{
echo...

For datecalc, I think there are examples in the FAQ.

If you have perl, perhaps try...DATE3=$(perl -e '@f=localtime(time-(86400*7));printf "%02d%02d%02d\n",$f[5]%100,$f[4]+1,$f[3];')

The time zone "trick" is not a reliable method of performing date arithmetic.

Have a look at the FAQ:...

Just pipe the ls through the awk command as posted by NareshN

Try...$ head file[12]
==> file1 <==
999
111
222
333
111
444

==> file2 <==
555
000

$ awk '/111/&&!c++{$0=$0 s};1' s="$(<file2)" file1
999
111 555
000
222
333
111

Perhaps try md5sum, e.g...md5sum -t files* | awk 'a[$1]{printf "%s and %s are the same\n",a[$1],$2;next}{a[$1]=$2}'

Try...awk 'BEGIN{FS=OFS="\t"}$3~s{$6=r}1' s='common/bin/my/home' r='happy Home' sample.rpt

The same code reformatted via gawk --profile gives... # gawk profile, created Wed Jul 25 09:58:45 2012

# BEGIN block(s)

BEGIN {
f1 = 0
i...

Try...awk '$1~/^RBE/{f=1}$1!~/^RBE/&&$1~/[A-Z]/{f=0}f' nastran1.bdf > rbe.data

Try...paste -d '|' File1.txt File2.txt | awk -F '|' '{c=NF/2;for(i=1;i<=c;i++)if($i!=$(i+c))printf "line %-5s field %s\n",NR,i}'

You could probably take out the $1=$1 since the input and output field separators are the same.

Try...awk -F: '$3~/EMPLID/{split($3,a," ");printf "%s,",a[3]}$2~/^ ORA/{print $NF}' file1

Try...$ cat file1
:
select col1 , col2 from /* selecting columns from the table1 */ table1;
:
/* etc1
etc2
*/
:
select col1 , col2
from /* selecting columns from the table1 */...

Try...$ echo 'oracle=user=name/pa/ssword@database' > sample.cfg

$ eval $(awk '/oracle/{
if(match($0,/=[^/]*/))
printf "user=\047%s\047\n", substr($0,RSTART+1,RLENGTH-1)
...

Try...$ echo 'oracle=username/password@database' > sample.cfg

$ set -- $(awk -F '[=/@]' '/oracle/{print $2,$3,$4}' sample.cfg)

$ echo user is $1, pass is $2, db is $3
user is username, pass is...

Choose a temporary delimiter that does not exist within the file..paste -d '~' File[123] | awk -F '~' '{printf "%-39s%-20s%-20s\n",$1,$2,$3}'

This should work for any size...$ cat file1.txt
var1 var2 var3 var4 var5 var6
A G A T G T
G A A A A A
A A A A A A
G A G T A T

$ awk 'NR == 1 {
split($0, var, FS)
...

All in one...awk 'BEGIN {
FS = "_"
fmt = "%sTime: %s Host: %s Instance: %s Dirs: "
}
{
if ($4 != prev) {
printf fmt, (dirs?dirs ORS:""), $4, $1,...