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It looks like there is a mismatch between the Locale that was used when creating the file and the Locale used when running your awk script.

Try running your awk script again with the LC_CTYPE...

Hi,
Try:
awk '{for (i=2;i<=NF;i++ ) print $1,"\t",$i}' file
Regards.

$ awk -F"\n" -v RS="</s>\n" ' { print NR,NF-2 } ' file
1 5
2 6

Hello owwow14,

Following may also help you in same.

awk '/<s>/{getline;while($0 !~ /<\/s>/){A++;getline};print A;A=""}' Input_file


Output will be as follows.

5
6


Thanks,
R....

awk -f ow.awk myFile where ow.awk is:

$0 ~ "<s>",$0~"</s>" {c++}
$0 ~ "</s>" {print c-2;c=0}

Any attempts from your side?

---------- Post updated at 17:21 ---------- Previous update was at 17:16 ----------

Be it as it may... this one is not too daunting. Try awk '/<s>/ {ST=NR}...

Hello owwow14,

Could you please try following, not tested though.


awk '{if($1 !~ /[[:punct:]]/ && $1 !~ /[[:digit:]]/) {print $0}}' Input_file


Thanks,
R. Singh

awk can write to whatever file you please.

awk 'L && (L != FILENAME) { close(L) }
{ L=FILENAME }
{$(NF+1)=1 ; print > L ".new" }' *

This will create "filename.new" for each "filename" fed...

Hello owwow14,

Here is an awk approach for same.


awk 'FNR==NR{A[$1]=$0;next} ($1 in A){print A[$1]}' fileA fileB


Output will be as follows.


adventures com|hum
adversity ...

Hello owwow,

Following may help.


awk '($4 ~ /^N.*/){$2=$2"-x"} 1' OFS="\t" filename


Output will be as follows.


1 HOW-x _ NNP NNP _ 3 nn _...

Try awk 'NF==0 {next} $1==1 && NR>1 {print "\n"}1' file

You could modify your awk like this:
awk '!NF{print; next}{print $4 "\t" $1 "\t" "-" "\t" $2 "\t" $3 "\t" "-" "\t" $5 "\t" $6 "\t" "-" "\t" "-"}' FS='\t' file

or

awk '!NF{print; next}{print...

Try using $0 instead:-
awk '{print $0 "\t" "1"}' file


Does that give you what you need?


Robin

Try awk '{$(NF+1)=1}1' file
pvb 1 2 3 4 5 ....... 300 1
fdh 3 4 5 2 4 ...... 300 1
dfk 2 3 4 2 6 ...... 300 1

It seems that you only want to change the last character on each line, but you don't restrict the search REs to match EOL and three of your substitutions are missing closing slashes. Try:
sed...

Hi Yoda,

If possible could you please explain your code line by line.
What this A[++c] will stores .. like this...

Regards,

awk '
{
A[++c] = $1
}
END {
for ( i = 1; i <= c; i++ )
{
for ( j = 1; j <= c; j++ )
...

Can you please explain more...because, from the data you shown above, how do you get the result you provided for identical cols 1 & 2.
Anyways, if you want unique col 1 & 2
awk '! a[$1 $2]++'...

If you do not mind to grep four times, this may could help you.

TP=`grep -c "1[[:blank:]]\{1,\}1$" infile`
TN=`grep -c "0[[:blank:]]\{0,\}0$" infile`
FN=`grep -c "0[[:blank:]]\{0,\}1$" infile`...

No, there isn't: grep is for filtering lines according to some rules, usually a regexp. What grep can do is: return all lines which exhibit a certain pattern. What grep cannot do: summarize content....

sed 's/+/ /' file


replaces first + to a space...

Hi, try:
sed 's/+/ /' file

Something like this?
awk '{sub("+"," ")}1 ' file

Hello,

Following may help also.


awk 'NR==FNR{a[$2]++;next} ($2 in a){if(a[$2] > 1) print $0}' file_name file_name



cat big 24
cat red 63
dog big 34
fish red 294


...

$ awk 'FNR==NR{A[$2]++;next}A[$2]>1' file file
cat big 24
cat red 63
dog big 34
fish red 294


edit *I just see yoda's approach and mine are same