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The usual approach is to put them either BEFORE the BEGIN rule, or AFTER the END rule. Performance-wise, it doesn't matter. You might want to have a look at User-defined - The GNU Awk User's Guide...

Another option which also seems to work:
awk '{str = str FS $4}!(NR%5){print "peak" ++c str; str=""}END{if (str) print "peak" ++c str}'

awk '{ for (i = $2; i < $3; i += 100) { print $1, (a[NR]++ ? i + 1 : i), i + 100 }'

Assuming that you are interested in the last field of rows containing "Thermal thickness"
awk '/Thermal thickness/ { Tt = $NF }'

You could start with:
awk '{a[$3 " - " $6]++}END{ for (i in a) print i, "=", a[i]}'

You can try:
awk 'BEGIN{ print "sL0", "dL0", "Tb","Tu"}/sL0.*dL0/{sL0=$3;dL0=$6}/Tb.*Tu/{ print sL0, dL0, $3,$6}'

This works for me in bash: echo "'"${msg//\'/}"'"

This works for me (using gawk):
gawk -F',| ' '!(a[$1,$2]++ + a[$2,$1]++)'

I just tried this with GNU sort and awk and it seems to work fine:
sort -r -k5 t3 | awk '!a[$1,$3]++'PS: This record has no space between "Italy" and the pipe character.
Italy| John | 08:22:12:349

About how to print: "last row with fifth column; in each file":
END{ print $5 }or in case you are using gawk 4.x:
ENDFILE{ print $5 }

If I understood correctly, you could try this:

awk '$2>($6-1000000) || $2<($7+1000000)'

While thinking twice, I came to the conclusion that the above should better read

awk '$2>($6-1000000)...