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In Solaris 10 you must use the Posix variants /usr/xpg4/bin/grep and /usr/xpg4/bin/awk. The ones in /usr/bin/ are from old Unix SysV 4.0.
Especially /usr/bin/awk is a link to /usr/bin/oawk (already...

As I understand the requirement it should be
fgrep -vxf a.out b.out > c.out
No RE match, and full line match.
The difference is visible if b.out has a line
fa

You need -f to do this. /usr/xpg4/bin/grep has a -f option.

In your example there were also:
-rw-r--r-- 1 mailsrv mail 189438124 Nov 2 2012 mail.log.31102012
-rw------- 1 mailsrv ...

Try /usr/xpg4/bin/grep instead

Have you tried something like:
gzcat mail.log.*.gz | cat - mail.log*[!g][!z] | grep -f a.out > c.out

You will probably need to write a perl script to convert the date to epoch time
like this (name it strepoch.pl):
#!/usr/bin/perl
my @months = ("JAN", "FEB", "MAR", "APR", "MAY",
"JUN","JUL",...

It's pretty straightforward to add the file writting:
#!/usr/bin/python

import re
import sys
from datetime import datetime
import time
strptime = lambda date_string, format:...

I modified your file to make the test posible:
# cat a.txt
Jan 9, 2013 23:59:59 PM com.sun.uwc.common.auth.IdentitySSOAuthFilter doFilter INFO login:220.255.2.108:null:login successful
Jan 9, 2013...

$ sed 's/@.*\//\//' test
user/ris1/INBOX
user/ris2/INBOX
user/ris3/INBOX
user/ris4/INBOX
user/str1/INBOX
user/str2/INBOX
user/tg4/INBOX

Try this:

gzip -dc http.log.20110808.gz | nawk ' /@/ { sub("^.*] ",""); sub(" .*", ""); if(!($0 in E)) print; E[$0]} ' > uniqueemail.out

please use tag, otherwise it is really hard to read it

---------- Post updated at 01:41 PM ---------- Previous update was at 01:23 PM ----------

put the patterns inside a text file ( for...

hmm... start from the basic unix commands and read about the control statements and some basic tutorials and examples.. ( just google it )
search this forum for "new to unix".. you see lot of...

nawk -F"/" '{if($0!~/@/){print $1"/"$2"@newdomain.com/"$3}else{print $0}}' test01.out

Try (not tested I'm on windows now):
sed '/@/! s|/INBOX|@newdomain.com/INBOX|'

One way you can start is learning regular expressions.

Here is another way of solving your problem using 'sed':
sed '/@/d' Input_File

One way would be..
awk '!/@/ {print $2}' inputfile > outfile

Dear Mr 47,

Please try this simple code for retrieving unique information.


gzip -d http.log.20110808.gz ;cut -d " " -f9 http.log.20110808 |uniq > http.log.20110808_updated

You can use zgrep also


/user/ahamed> zgrep -o "[^ ]*@[^ ]*" http.log.20110808.gz
igchung@abc.com
sastria9@abc.com
sastria9@abc.com
sastria9@abc.com
pntcdor1@abc.com
pntcdor1@abc.com...

zcat http.log.20110801.gz | nawk...
OR
gunzip -c http.log.20110801.gz | nawk...
OR
gzip -dc http.log.20110801.gz | nawk ...

Note: if file is gzipped as extension seems to imply you man need to pipe output of gzip -d to these solutions.

Try to use nawk instead of awk.

With grep/sort/uniq:
grep -o "[^ ]*@[^ ]*" http.log.20110808.gz | sort | uniq

With awk:
awk ' /@/ { sub("^.*] ",""); sub(" .*", ""); if(!($0 in E)) print; E[$0]} ' http.log.20110808.gz
...

Yes it is. It "cats" a file (a useless use of cat), cuts (extracts) the second field assuming the file is comma-separated, then, for each sequence of non-unique records shows a count of how many...

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