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Just in case, note that the OP specified sendemail, not sendmail. Perhaps it's a typo, but there is such a program and it is available via ubuntu's package repositories.
...

Polling the folder and hoping that everything is done is asking for trouble. If you actually care about not copying over a half-written file, you need an atomic step.

First of all, the directory...

If the file uses a tab delimiter and there is only 1 per line:
sed 's/\./\t/3; s/\t.*\t/\t/' file
That isn't portable sed, because \t is primarily a GNU extension. However, if it worked for you,...

CS and DS do not need a type member. Whenever CS and DS are being used directly, the code using them already knows what they are. Only ignorant code inspecting the union needs access to a type flag....

If you are using bash, and if there's no bash-specific code, try dash or ksh93. Bash isn't an efficient shell.

We can't possibly make any targeted recommendations without knowing something about...

If this task is performed regularly, you should consider using a dedicated filesystem. When the time comes to wipe it, instead of rm use mkfs (or newfs, or whatever tool your system uses to create a...

echo is usually a shell built-in and not subject to that limit.

Regards,
Alister

AWK's arrays are associative and its subscripts are strings. i does pop into existence, but, in that string context, its undefined value is converted to an empty string.

awk 'BEGIN { a[i]=5; print...

For a numeric sort, there's no need to remove leading zeroes.

Regards,
Alister

Two things. First, the -c option, which complements [:alpha:], so what is matched is everything that is not a member of [:alpha:].

Second, \n* must be bracketed. With the brackets, it represents...

Welcome to the forum.

Your post is devoid of specifics, so don't expect much targeted advice.

Are you using the CPUID instruction to detect AVX? That should work. For the specifics, there are...

Professor? This should probably have been in the homework forum.

Seems a "classmate" has showed up with the same data.

Regards,
Alister

It seems like your friend posted here as well, https://www.unix.com/shell-programming-and-scripting/247112-help-sed-command.html

What a coincidence. For the sake of your projects, you should both...

Nevermind me. I didn't register the "next".

Regards,
Alister

---------- Post updated at 07:35 PM ---------- Previous update was at 06:59 PM ----------


You are correct in correcting me;...

After re-reading the OP's previous two posts, I'm not certain if I correctly understood the task. If I am mistaken, apologies for the noise.

What I have in mind is the following scenario:

1...

As far as I'm concerned, unless you demonstrate that you have put forth some effort to solve your own problem, you can continue to wait.

We are here to help, but we are not a free, script-writing...

Another, slightly simpler, sed alternative:

sed 's/.*(//; s/).*//' file

Even if you set that up correctly, on your system, according to the diagnostic message, mkdir isn't under the /usr hierarchy.

More importantly, as I said, there are multiple errors in your attempt...

Since the strings tested aren't regular expressions, using the regular expression operator is, at best, unnecessarily expensive. At worst, if the strings are allowed to contain regular expression...

You can group them with { ... ; } or ( ... ) or you can use exec.

Regards,
Alister

If the following script is problems.sh:

mkdir newdir && cd newdir

cat <<EOF > file.txt
*.txt


a b .txt
EOF

echo BEGIN CORRECT SOLUTION
sed 's/\.txt$/_'$(date +%m%Y)'&/' file.txt...

If we are going to be precise with regard to formal language theory, then you are mistaken. Neither POSIX Basic Regular Expressions, nor the "extended" dialects implemented in perl, python, php,...

A simple sed solution:

sed 's/\.txt$/_'$(date +%m%Y)'&/'

Regards,
Alister

---------- Post updated at 12:31 PM ---------- Previous update was at 12:19 PM ----------


That's an extremely...

That code is vulnerable to pattern matching metacharacters. For this approach to work with arbitrary text, it is necessary to double-quote the nested parameter expansion.

$ s=*****a
$ echo "$s"...

That's not quite right. Both instances of *.* should be *..

Regards,
Alister