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I would suggest using $1 and $2 instead of $0 to discard any blank spaces in any record:
awk '!A[$1,$2]++' file

Try:
sort -un inputfile

Hi guy,
As anbu123 said, if your data is sorted, you code is correct.
Mostly we do this to select non-duplicate records
awk '!a[$1]++' inputfile

Note that although you need to remove the commas from your input before adding the values to your total, awk is happy to print your results with or without thousands separators. As an example, if...

In first command var=$1 and then gsub is used it means $1 will remain unchanged, in second command if $1 contains , then its removed, and $1 itself will be modified

look at the difference copy of...

That var will hold the count of substitutions that gsub has made on the string it worked upon. The string itself will be modified and thus holds the result.

Try like this

$ printf "%s\n%s\n" 10,250.00 20,103.15 | awk '{var=$1;gsub(/,/,x,var);print var}'
10250.00
20103.15


if you assign directly as greet_sed said it gives you a count of...

you can.
variable will results in to number of times the substitution has been made.
For ex:
echo "hi,this,is,name" | awk '{ a=gsub(/,/,"");print a}'
3

remove the commas:
awk '{gsub(/,/,"");subtot+=$1}END{print subtot}' file

Try

$ awk '{sum+=$1}END{print sum}' file

if comma is there then use this

$ printf "%s\n%s\n" 10,250.00 20,103.15 | awk '{gsub(/,/,x,$1);sum+=$1}END{print sum}'
30353.2

Reformatting Scrutinizer's code and adding comments:
awk ' # invoke awk program and start script to be run by awk
/Output view:/ {# When an input line contains the string "Output...