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I'd propose to drop the "command substitution" $( ... ) as it's not needed in above construct.


If you have all target lines in a file, and you are sure they occur not more than once in the large...

I would go further:-if $(grep -q "now is the time" 1000linefile.txt)
then
echo "It's a HIT"
else
echo "Missed"
fiThe extra benefit is that the -q flag will cause the grep to exit...

a bit simplified:

if [ $(grep -c mySearchPattern myFile) == 0 ]; then
echo 'not found'
else
echo 'found'
fi

As general note - some bash regex strings fail when used directly on the command line. Spaces in regex are an example.
It is probably best practice to make them variables:
bash - Capturing Groups...

bash supports regex, tried that?

string="SNMPv2-MIB::sysObjectID.0 = OID: SNMPv2-SMI::enterprises.9.1.1745"
regex1="sysObjectID"
regex2="[0-9]{4}$"
if [[ "$string" =~ $regex1 ]] then
[[...

How about
while read line
do [[ "$line" =~ sysName ]] && sysN=${line##* }
[[ "$line" =~ sysObjectID ]] && sysO=${line##*.}
[[ "$line" =~ sysDescr ]] && {...

I'm afraid - no. That's a feature of bash - I can't talk for other shells.

simple would be..


sed -ne '/is/p' -e '/for/{p;q}' filename

If you read the entire file into an array
you can print the array like that - without a loop.
@lines = <IN>;
print grep /\Q$ARGV[0]\E/, @lines;
Or even directly from the file
print grep...

#!/bin/perl
$err=1;
open (IN,"peeplist") or die;
while (<IN>) {
if (/\b$ARGV[0]\b/) {print; $err=0;}
}
close (IN);
if ($err==1) {print STDERR "not found\n"}
exit $err;This uses perl's $_...

This is listed in perlfaq.

have a look How can I tell whether a certain element is contained in a list or array?...

Depending on how many <NAME> lines there are in the input file, you might have to close the output files when you're done writing to them:
{if(FN)close(FN);FN="File"++i".txt"}

Reedited - fine! Do you think you find the right answer with the starting point given above?

sed 's/^[^ ]*/&,/' file

You can also do that slightly shorter with:

$ awk '$1=$1","' file

but neither will maintain the spacing between fields. Perhaps using awk's sub function would be the answer.

This seems a bit...

You can use awk instead:-
awk ' { $1 = $1","; print; } ' input_file