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Hi JSKOBS...

Not quite exactly what you are looking for but a little bit of lateral thinking creates this.
#!/bin/sh
# awk_shell.sh

: > /tmp/myfunc
chmod 755 /tmp/myfunc

cat << "EOF" >...

How about:
$ echo ' <APPLICATION="APPLSG" SUB_APPLICATION="DLY" JOBNAME="DPL_BN_RE_CCMS_SA" CMDLINE="run_job.ksh %%PARAM1 %%PARAM2" TASKTYPE="Command" />' | awk -F'"' '{for(i=2;i<NF-2;i=i+2)...

How aboutawk 'awk '
NR == 1 {printf "%-40s%-23s%-23s\n", "Job name", "Created on", "Modified on"
}
/^Job name/ {printf "%-40s", $3
}
/^Created on/ ...

So? Why don't you insert it into the proposal?

Would this come near of what you need:
echo -e "MMS000101S0203430A|20180412E|\nMMB0001INVESTMENT||107-86193-01-03|\nMMB0001FUND||107-86193-04-01|\nMMC9991 " |
awk -F'|' -v OFS=, '
/^MMC9991/ ...

Try also
awk -F, '{T[$1] = T[$1] ORS $2} END {for (t in T) if (!(T[t] ~ t)) print substr(T[t],2)}' file
B2
C2

awk -F, '{a[$0]=$0} $1==$2 {b[$1]=$2} END {for (i in a) {$0=a[i]; if (!($1 in b)) print $2}}' file

Hello JSKBOS,

Following may also help you on same.

awk '{printf("%s%s\n",FNR==1?"START OF LINE":"",$0)' Input_file
Thanks,
R. Singh

RudiC already told you how to do it but you might profit from understanding why your code did not work:

The reason why this doesn't work is that "NR" is only updated when records are read....

Why not
awk 'NR == 1 {print "START OF LINE"} 1' file?

EDIT: or
[ -s "$FILE" ] && { echo "START OF LINE"; cat "$FILE"; }

Another idea, very efficient, is to exit after the print.
awk -F"=" '/\$Temp/ {print $2; exit}' /DIRECTORY/*

Hi RudiC,
When JSKOBS said ""decimal" have two decimal points", I think the requirement was a single radix character and two decimal digits following it. There was also a requirement for zero or...

How about
awk -F\| '
{if (!sub (/^[0-9][0-9] [A-Z][A-Z][A-Z]/, "&|", $2)) $2 = FS $2
if (!sub (/[0-9.]*[0-9][A-Z]* *$/, "|&", $2)) $2 = $2 FS
}
1
' OFS="|" file

If is not loop. Its conditional statement.

I guess, APPEND is having string.

please try this

#!/bin/bash

echo -n "Enter the String : "
read APPEND
LENGTH=${#APPEND}
if [[ -z...

Could you use pgrep?

ps -l -p$(pgrep -d, process_name)

will list all processes named "process_name"
You want sub-processes of "process_name"?

ps -l --ppid $(pgrep -d, process_name)

And...

ps -ef displays args, so try
ps -eo etime,pid,args | grep "[d]sjob.*run"
The [ ] trick prevents from matching the grep process argument.

None, except output formatting
From the linux man page for ps(1)


To see every process on the system using standard syntax:
ps -e
ps -ef
ps -eF
...

Happy with the result?
Looking back at it, it could be slightly simplified:
awk '{T = substr ($0,1,7) ; gsub("[[:alpha:]]","X"); print T substr ($0, 8)}' file

Hello JSKOBS,

Could you please try following and let me know if this helps you.

awk '{P=substr($0,1,7);num=split(substr($0,8), A,"");for(i=1;i<=num;i++){if(A[i] !~...

To add a different take: if you mean by "non-printable" characters those which cannot be displayed because of your locale (like, for instance, UTF-8-characters with a "C"-locale) you can use seds...

You haven't really described what you consider non-printing characters. In most locales, RudiC's suggestion will select any lines that contain any character that is not <space> and is not in class...

How about
grep '[^[:print:]]' filename?

I think it shows total as well :)

Another solution:

printf "%s|%s\n" $(wc -l file.txt asdf.txt lkjh.txt bvcx.txt|sed '$d') >> temp.txt

Hello JSKOBS,

If you want simple and sober line counts the you could use wc command as follows.

wc -l Input_file1 Input_file2 Input_file3 Input_file4 | grep -v "total"
Output will be as...