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A slight variation:
echo "2011-12-31T13:00:09Z"|sed -e "s_\([0-9]\{4\}\)-\([0-9]\{2\}\)-\([0-9]\{2\}\).\([0-9:]\{1,\}\).*_\3/\2/\1 \4_g"
31/12/2011 13:00:09

Ugly as sin, but effective

echo "2011-12-31T13:00:09Z"|sed 's/\([0-9]\{4\}\)-\([0-9]\{2\}\)-\([0-9]\{2\}\)T\([0-9]\{2\}\):\([0-9]\{2\}\):\([0-9]\{2\}\)Z/\3\/\2\/\1 \4:\5:\6/'

This way works using the Korn shell:


for i in *-DATE*;do mv $i $(echo $i | sed 's/\-DATE//');done

If you use -e only, it is going to print the output on stdout, but will not change updated_list. If you use '-e -i', it's gonna do editing-in-place and print nothing to the screen, bot modify the...

Below code will take backup of inputfile as inputfile.old before processing and then modify the inputfile
perl -p -i.old -nle 's/\/(\w+)(\d{8})/\/\2\/\1\2/' inputfile

Hi,

Here a solution using 'perl'. The code uses the 'DateTime' module. Perhaps you need to install it from CPAN.

I suppose date is in format: YYYY MM DD. Tell me if I'm wrong because otherwise...

Please post an actual sample of your input and the requested output data. From the looks of your code it's not quite as described.