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That code is an absolute mess. It's almost as if you're trying to make it difficult for us to help. The very, very least you can do is use sane indentation.

I didn't scrutinize it, but two things...

If you by "value of the file through path" just mean the filename, then its:
var=$(basename "/path/to/file with spaces")
If you mean the content of the file, its:
content="$(cat...

Awk solution

you may try

your files
$ cat manu.txt
ffrs44frfrf
123.33.44.3
$ cat katty.txt
d4r4ff5rf5
123.44.32.4
$ awk '{i++;split(FILENAME,A,".");printf (i==1)?"Host"FS A[1] "{"RS...

you have to use bc and you also need to check argument exist or not

try

#!/bin/ksh

check(){
if [ -z "$1" ];then echo "No user input exiting..";exit;fi
}

check $1

sum=0...

Your requirement is not quite clear.
The following reads numbers of files from arguments, or from stdin if no arguments are provided.
The numbers in files or stdin can be placed in columns or rows...

set -x
sort file*
+ sort file file~ file1 file1~ file2 file2~ file3 file3~ file4

sort takes any number of files to work upon (up to certain system limits). So, if unquoted,...

you can use cat

cat /path_to_file/*.type | sort ........so on

Dear I too confused :)

if you want to use it as variable do like this

my_new_ip_address=$( awk -F'.' '{m3=($3>m3)?$3:m3;m4=($4>m4)?$4:m4}END{print (m4>=254)?134 FS 123 FS m3+1 FS m4*0:134 FS...

Do you read the answers to your thread?

A different approach to the original question:
awk -F. '{n=256*$3+$4} n>m{m=n; ip=$0} END{print ip}' file*

output:
134.123.25.237

Not exactly. The while loop is side effect of the fact that awk reads a line from the input file and performs the actions associated with each set of conditions that match those conditions. So in...

$m4 ==254 { m4=0; m3 = $m3 +1}In awk $ is used to access fields, not variables - if m4 is 254, $m4 is a reference to (empty) field 254.

Also, consider what you want to do in this case if octet 3...

ip=`head -n1 file.dat` # read ip address from file
end=${ip##*\.} # delete everthing before last dot (leaving 234/235)

while (( end++ < 254 )); do # while the 234/235 is less than 254...