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I've made an assumption:
each record consists a 6 field row followed by an optional 5 field row


awk -F" " '
NF==6 {
if(getline nl) {
if(split(nl, v, " ") == 5) for(i=2;i<7;i++) $i...

#!/bin/bash

echo -n "Read the letter >(enter a or b or c) "
read letter

# One easiest way to Compare
for i in a b c; do
[ "$i" = "$letter" ] && break
done

# ok will be zero if true...

arg1 OP arg2
OP is one of -eq, -ne, -lt, -le, -gt, or -ge. These arithmetic binary operators
return true if arg1 is equal to, not equal to, less than, less than ...

awk 'sub(/DISK-A */,X)' file