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You are falling into the same trap as mohtasims (in whose thread you have answered): you confuse the CONTENT of a file and its REPRESENTATION.

You construct a stream of characters forming your...

For your sample input, where you want to perform an alphabetic sort on the 1st two characters of the 2nd field as the primary key, a numeric sort on the remaining characters in the 2nd field as the...

An adaptation of the GNU awk script in post #2:
awk '
/ FTR *$/ {
s=$0
f=""
while(match(s,/[^ ]+ */)) { # use greedy match with field width and trailing spaces to find maximum...

Hi, try (using GNU awk):
awk '
FNR==1 {
s=$0
while(match(s,/[^ ]+ */)) { # use greedy match with field width and trailing spaces to find maximum width
f=(f?f OFS:x) RLENGTH ...

Assuming that none of your headings are substrings of any earlier (from left to right) headings, you could try something like:
awk -F' +' -v LM="$(getconf LINE_MAX)" '
t == 0 && NF > 1 {
# 1st...

Yes, the sort wasn't right. Try:
nawk '{p=$0;$1=$2 FS $1; gsub(/[0-9]+/," &",$1)}{print $1,p}' file | sort -k1,1 -k2,2n -k3,3 -k4,4n | nawk '{print $5,$6,$7}'



---

On Solaris one needs to...

After some reformatting and outlining (it helps!) I came up with the following quick fix:
#!/usr/bin/ksh
awk '
{
D[$2]++
A[$4]++
C[$3]
B[$4,$3,$2] = B[$4,$3,$2] ?...

Assuming TERM is set in your environment to correctly indicate your terminal or terminal emulator type, the following should work:
#!/usr/bin/ksh
addword() {
tput clear
if [ "$input" != "" ]...

Single awk can do your job, if order doesn't matter then you can process in END block also, current script reads same input twice and take care of output order.


Input
akshay@nio:/tmp$ cat...

Try awk ' {I[$1]
for (i=1; i<=Ccnt && $3 != C[i]; i++);
if (i > Ccnt) C[++Ccnt]=$3
T[$1, $3]=T[$1,$3]...

Consider the following:


PID=$$
# The self killer
(sleep 30;kill $PID)&

# The program
while [ T ]; do
date
sleep 2
done

First: it is highly unlikely that the PID is recycled so fastly. PIDs are - for a reason - supposed to be almost random.

Second: even this small chance is further reduced to absolute zero because...

awk 'NR == FNR {a[$0]; next}
{if(! (FNR in a)) {print}}' list.txt main.txt

With awk
awk '/(HI|FR|GO|TAT)/ {c=2} (c!=0 && c--!=0)'

Not getting output using /usr/sfw/bin/ggrep -E -A1 ...?

Can you please show what you have done, including some sample from the file you are searching on?

awk '{for(i = 5; i <= NF; i++) {split($i, a, ":"); $i = ""; split(a[2], b, "");
for(j = 1; j <= length(b); j++) {if(b[j] == 1)
{$i = ($i == "") ? (a[1] ":" length(b) - j) : ($i FS a[1] ":"...

See this might help you

awk '

function bits2str(bits, data, mask)
{
if (bits == 0)
return "0"

mask = 1
for (; bits != 0; bits...

This works in the bash shell. It is a one-off hack, IMO. perl or some other interpreted language would be more efficient.

#!/bin/bash
#obase.shl - convert to binary from hex
while read rec
do...

$ sed "s/TRS-[^ ]* //g" file
23 345 235
45 423 000
76 300 234

@RudiC : in first tag he wantsCC=OA0,ON0 to come first



Here is a code which takes care about order

awk ' {
A[$2]++
B[$2 FS $3] = B[$2 FS $3] ? B[$2 FS $3] "," $1 : $1...

Way more clumsy than I intended when I started, but it will keep the order of occurrences of $2. Try awk '!A[$2]++ {IX[++MAX]=$2}
{B[$2 FS $3]=B[$2 FS $3]","$1}
...

awk '{
for (i = 3; ++i <= NF;)
print $1, $2, $3, $i
}' infile

If field1 is sorted then this would work

$ cat <<test | awk '$1!=p{print NR == 1 ? "category" OFS $1 : "ok" RS RS "category" OFS $1}{print "item",$2;p=$1}END{print "ok"}'
CAT1 FRY-01
CAT1...

Or try:
awk 'cat!=$1{if(cat){print "ok" RS} cat=$1; print "category ", $1} {print "item", $2}END{print "ok"}' file

As joeyg pointed out, end-of-lines might be problematic. Try a modification of Akshay Hegde's proposal:awk 'FNR==NR{A[$1]=$2;next}{for(i in A)if($0~i"[^0-9]|$")sub(i,A[i],$0)}1' file1 file2