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Linux:
$ /usr/bin/printf "%05s\n" 123
/usr/bin/printf: %05s: invalid conversion specification


---------- Post updated at 09:12 ---------- Previous update was at 08:11 ----------

Perhaps you...

If you save the following in a file named tester:
#!/bin/ksh
width=${1:-5}
printf '%s\n' 123 12345 12345678 "" S12 | awk -v w="$width" '
{ if((len = length($1)) >= w)
printf("%s\n", $1)...

As I mentioned in post #3 above, this is not surprising. You will probably also find the same difference in the printf family of functions in libc on those systems (for C and C++ programs using...

The standards describe the 0 flag in generic printf format arguments as follows:

Since the s format conversion specifier is not in the above list and the awk printf function description does not...

Yes... like most gcommands.. gnu version often offers more options and so behaviour may not be like standard UNIX commands, think of gtar etc...

Your temporary filesystem appears to be too small. You can specify an alternative location with sort's -T option...

... or try something like this:
awk -F\| 'NR==FNR{A[$1]; next} $1 in A' R1 R2

Hi,

Join needs the default sort order, not a numerical one.. Try this if you are using bash / ksh93:
join -t \| <(sort -t\| -k1,1 R1) <(sort -t\| -k1,1 R2)

It will not.
awk 'BEGIN {
CONVFMT="%-20.6f"
a=19
b=20.5
printf ("a = %s\n",a)
printf ("b = %s\n",b)
}'

a = 19
b = 20.500000
Integers get converted to strings as integers, irrespective of...

Use f instead of d in printf which stands for "floating point".

BashFAQ/082 - Greg's Wiki (http://mywiki.wooledge.org/BashFAQ/082)

See if this gives any information you're looking for:
Useless use of backticks. (http://partmaps.org/era/unix/award-example-backticks.html)

Hi, try:
sort -t \; -k3.2,3.3rn infile | awk -F\; '!A[$4]++'
Make sure there are not spaces in the input file.

Hi,

Try this one,


awk 'BEGIN{FS=";";OFS=";";}{split(/\;/,a,c[$4]);if(a[3] < $3 ){c[$4]=$0;}}END{for( i in c ){print c[i];}}' file


Cheers,
Ranga:)