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bool login()
{
string user[10],password[10], user1, password1;
ifstream myfile("idpw.txt");

cout << "Please enter your username" << endl;
cin >> user1;
cout << "Please enter your...

printf "%0.2f" $price

Prints a value in 2 decimal places.

grep -i 'Supermarket B' infile.txt | sed 's/:/, /;s/:/, \$/'

# cat infile2
Chocolate:Supermarket A:5
Ice Cream:SuperMarket B:7
Banana:Supermarket B:3
# grep -i 'Supermarket B' infile2 | sed...

awk -F: '/Supermarket B/{$3="$"$3;print}' OFS=\, file | sed 's/,/, /g'

Pattern|Action|Meaning
/^Chocolate/|{$4=5}|For a line starting with "Chocolate", set the fourth field to "5"
1|-|1 evaluates to true. If no action is specified the default action is to print the...

It means on the line starting with Chocolate replace the first occurrence of the pattern with 5. The pattern is [^:]*, which means 0 or more occurrences (*) of any character that isn't ":"

---...

:b:
sed '/^Chocolate/{/:/s/12/5/4}' inputfile > outfile
Change the last number (here) 4, according to the position of 12 you want to change

You're right. I never remember that thing :D

Not that ugly :)
sed '/^Chocolate/s/[^:]*/5/5' file
(4th 12 is the fifth field, right?)

Well, I never saw that question coming ;) :D

sed starts getting ugly when you try to do this stuff.


$ awk -F: '/^Chocolate/ {$4=5}1' OFS=: file1
Chocolate:12:12:5:12:12:12:12

Depending on how exactly you want to edit:
If you want to change all line having "Chocolate:5:5" to "Chocolate:5:10"

sed 's/Chocolate:5:5/Chocolate:5:10/'


OR change all lines "Banana:33:3"...

$ cat file1
(Product:Price:QuantityAvailable) (: as delimiter)
Chocolate:5:5
Banana:33:3

$ sed "/^Chocolate/ s/[^:]*$/14/" file1
(Product:Price:QuantityAvailable) (: as delimiter)...

Yes, in the case of bash use the second option...

You're welcome! If you have ksh93 (which is the only shell with floating point arithmetic) use:
totalsales=$((price * qtysold))otherwise:
totalsales=$(echo "$price * $qtysold" | bc)

Try printf:
awk -F: '{printf "%-25s %-6s %3d %s\n",$1,$2,$3,$4}' infile
while IFS=: read name age gender country
do
printf "%-25s %-6s %3d %s\n" "$name" "$age" "$gender" "$country"
done <...