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You need to use "command substitution" (c.f. man bash). Try
final=$( echo "scale=4; ($sum1 / $sum2 ) * 100" | bc) or, if you have a recent shell, a "here string"
bc <<< "scale=4; ($sum1 / $sum2 )...

Or, reading input just once:
awk -F, '{++C[$1]; T[$1] = $0} END {for (t in T) if (C[t] == 1) print T[t]}' file
877,RIBDF,E28

Hello mutley2202,

Could you please try following and let me know if this helps you.

awk -F, 'FNR==NR{++A[$1];next} ($1 in A) && A[$1] == 1{print}' Input_file Input_file
OR(more precisely) ...

Hello mutley2202,

Could you please try following and let me know if this helps you. Let's say following is Input_file.

cat Input_file
12
123 FP
11
10 RFP

Then i is a variable whose...

Try:
awk -F. '{printf "%03d.%03d.%03d.%03d\n",$1,$2,$3,$4}' file
or
awk '{for(i=1; i<=NF; i++) $i=sprintf("%03d",$i)}1' FS=. OFS=. file

Isolate the number pattern and place it inside the capturing group in red.
$ cat test.file
ses:3317] start call ms <0781234567> id < 13102 > id2 <0a23> index 858
ses:3318] start call ms...

If we are dealing only with 10 digit numbers lead by "078", that will work. If not, we need to know more to identify the digits to be replaced, like "the first angle bracketed number in the resp....

For the sample output you showed us (with the output being 10 "x"s surrounded by angle brackets), the following should work with any version of sed that conforms to the standards:
sed...

You could open both at once, perhaps, using open() instead of backticks. How about this:

open(CMD1, "./ssh_run_cmd2.exp xxx.xxx.xxx.xxx $log "show association peer-address $ip", "-|");
...

join file1 file2for more options see
man join--
join -t " " file1 file2seems to preserve the format. NB the key in field#1 is not repeated.

awk reads and processes every single line in the input stream. A line starting with NE : is stored in the variable P, overwriting the last one, then that line's processing is abandoned and the next...

The suggestions works if there is always one line without NE :. If there are more lines then P gets printed for every following line, so a provision would need to be made if that could be the case.....

Like so?
awk '/^NE :/ {P=$0; next} {print P}' file
NE : V0004
NE : V00005

Please show us what you have. There are hundreds of ways to do this, but to understand what you're doing and how to give you a working solution for your problem it would help a lot to see what...

You cannot easily 'enter a password' with ssh, it is built to bypass most attempts at that.
The passwd command is also that way. You will need to bypass those problems which involves some advanced...