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Just saying it isn't working isn't exactly helpful.

If the output of bppllist -byclient client1, 2, 3, 4, etc. is:

policy1
policy2
policy3
policy4
...


Then the following command (to...

Could this help ?
for i in $(cat clients_list)
do
bppllist -byclient client1 | awk '/^CLASS/{print $2}' | while read policy
do
bpplclients $policy -delete $i
done
done

All sed versions take
$ sed '1i\
NAME ID\
' textAll but certain (old) GNU sed.

$ uname
Linux
$ sed "1i NAME ID\n" text
NAME ID

mick 3424
noah 134
samuel 787
jack 434

Or use printf and cat
{ printf "NAME\tID\n\n"; cat inputfile; } > outputfile

awk 'BEGIN {print "NAME ID"} {print $0}' input.file
NAME ID
mick 3424
noah 134
samuel 787
jack 434


You can add \n after ID if you need an extra line after the header.

It's not awk, but here is a convenient way to do it:
$ paste -d , -s file
34,12,56,76,88

---------- Post updated at 02:28 AM ---------- Previous update was at 02:21 AM ----------

Best I can...

Check vgersh99 post in https://www.unix.com/shell-programming-scripting/220037-passing-value-variable-read-command-line-called-script.html

You can also try echo 1 | yourscript

--ahamed

Another awk
awk '/Gender/ {g=$NF;getline;i=$NF;getline;getline;print i,g,$4}' file
4512 m 04/23/2012
1256 m 012/10/2011
14523 F 01/20/2009

Use NF-1 in-place of NF:

awk '/Gender/{g=$NF}/ID/{id=$NF}/[Hh]ire/{print id,g,$(NF-1)}' file

Guru.

while read nm dt; do [ "$dt" == "$(date -d "last-monday" +"%m/%d/%Y")" -o "$dt" == "$(date -d "last-tuesday" +"%m/%d/%Y")" ] && echo $nm; done < employee_list

awk '$2==d1 || $2==d2 {print$1}' d1="$(date +"%m/%d/%Y" -d last-monday)" d2="$(date +"%m/%d/%Y" -d last-tuesday)" employee_list
Jack
Maneul
Eric

The date is a string, so in awk there would need to be double quotes around them if you want to compare it do $2. Although that would work, it would be better to use awk variables (for example...

For AIX:

List your HBAs:

lsdev -Ccadapter -l fcs*


Print the WWN:

lscfg -vl fcs0


You should be able to identify which is the WWN; have no output here at the moment.
You can cut the...

Here are a couple of ways to do what you want:
#!/bin/ksh
echo simplififed translation from given code
while read i
do grep $i /tmp/b | awk '{printf("echo mail -s \"%s is your new ID\"...

What about in sed?
Anyway try this,

awk '/^48/{t=1;next;}t==1 && $0 !~ /^[0-9]/{print;}/^[0-9]/{t=0;}' file

Cheers,
Ranga:-)

sed -i "s/^ *//g" inputfile
or
perl -i -pe 's/^\s+//g' inputfile

There should be lots of threads on this one. Did you try searching the forum?

$ nawk '/2011/ , /2012/ {if($0!~/[0-9]/){print}}' mylist.txt | tr " " "\n"
sara
phill
mike
bob
tala
ali
zula

$ nawk '/2011/ , /2012/ {if($0!~/[0-9]/){print}}' mylist.txt
sara phill mike bob
tala ali zula

You can try -r alpha@domain.com along with the mail command. But check in your man page as different OS would have their own meanings.

If the list of clients is long, or the client 'name' contains blanks, this would be a better way to read through the list. Also if the output of bpplclients is long the same applies. The grep isn't...

Hello ,
You want to do something like that . huh?
for CLIENT in $(cat clientlist)
do
for POLICY in $(bppllist -byclient $CLIENT | grep "CLASS " | awk '{print $2}')
do
...

Hi,

Try this one,


awk '/^sport/{a[p]++;}/^Month/{gsub(/Month *: */,"");p=$0;a[p]="0";}END{for ( i in a){print i,a[i];}}' Input_File


Cheers,
Ranga:)

Try:
awk '/Month/{m=$NF;A[m]=-1} {A[m]++} END{for(i in A)print i,A[i]}' infile | sort -rnk2
awk '/Month/{if(NR>1)print m,c; m=$NF; c=-1}{c++} END{print m,c}' infile | sort -rnk2

# awk '!/NAME/{a[$1]++};END{for(i in a)print i,a[i]}' mylist|sort -nrk2
Mike 3
Sara 2
Raya 1
Micheal 1
Fibi 1