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Either of these patches might work, although there are smarter ways

awk '{a[$2$3]++; b[$2$3]=$0}END{for(as in a) if(a[as]==1) print b[as]}' infile | sort -k2,2n

awk '{a[$2$3]++;...

If order is not important

awk '{a[$3]++; b[$3]=$0}END{for(as in a) if(a[as]==1) print b[as]}' infile

M4 1 3456
M8 2 7889
M5 2 456

one way below using split, other methods include parsing by regex..

try

awk -F"\t" '{split($10,a,";"); for (i=1;i<=length(a);i++) if (a[i]~/gene_name/) { split(a[i],b,"\"");x=b[2] } else if...

Close

awk 'NR%2{printf $0" ";next;}1' file

Adapted from a similar solution on this forum


awk 'NR>1{LN[$4]; HD[$5]; MX[$4,$5]=$2}
END { printf "%8s", ""; for (i in HD) printf "%8s", i; print "";
...

please use code tags from now..
can you see the extra tabs in your data?

Removing tabs with a pipe should give you unique list

cut -d'|' -f4 emp.1st | sed 's/\t//g' | sort -u

This looks like a simple case of paste

paste -d";" file* > output_combined

try

awk -F, '
{a[$1","$2]=a[$1","$2]?a[$1","$2] OFS $3:$3}
END{for (i in a) print i FS a[i]}
' OFS=";" file

care to give an example of what you are looking for? exact input and exact output samples would help.

Try, untested

awk -v x=0 '(NR == FNR) { if(length > x) x = length;next } { printf("%-"x"s\n", $0) }' file file

A crude way, I`m sure there is better solution

awk -F"X" 'NR==1{$0= $0" D"} NR>1{ $0=$0" "NF}1' infile| awk 'NR<2{print $0;next}{print $0| "sort -nk4,4"}' | awk '{print $1,$2,$3}'

this might work? untested..

find . -name "*.properties" | while read line
do
./operation.sh 775 "$line"
done

I will do this in 3 steps.

1. Extracting the first column from any of the files, add a blank line and store in a file.
awk 'NR==1{print ""} {print $1}' file1 > ../tmpcol1


2. Paste all col2...

In your old directory (dir1)

mkdir ../newdir

for file in *
do
awk '$20<40' $file > ../newdir/$file
done


Note that newdir will be same level as your olddir

Try

awk -F";" '$4=="02"{ sum+=$(NF-1)} END {print sum}' Input_file > Sum.txt

Please decide what your requirement is before posting, anyways,, for your latest req

awk -F";" '$4$5=="022015"{...

another solution

awk -F";" '{ sum+=$(NF-1)} END {print sum}' Input_file > Sum.txt

How about now

awk '{split($4,a,":"); if (a[1]>=24) print}'

maybe this will work too?

awk '/^\(/ {sub(/\(/,"");sub(/\)/,"")}1' infile

Can you try this?

I remember pulling this from the internet a long time ago, though never used it.

awk -vq='"' '
func csv2del(n) {
for(i=n; i<=c; i++)
{if(i%2 == 1) gsub(/,/, OFS,...

Hi Don,

I`m getting the the following result when I run the code in cygwin

$ cat tmp
a.sh start time is Fri Jan 9 17:17:33 CST 2015
a.sh end time is Fri Jan 9 17:47:33 CST 2015
Single...

Not tested, but maybe some form of the following might work ? Please try on a dummy set first..
Waiting on a second opinion

find /TGTDIR/ -maxdepth 1 -type -d -name '*' -print0 | xargs -r0 ls -t...

I want to edit the sample input slightly to accommodate NA missing values, and remove the leading spaces. For a finite number of columns you can of course use arr1, arr2, arr3 etc like you have used...

How about this

awk 'NR==FNR { a[$0]; next } { for (i in a) print i, $0 }' prefix root


A slower bash solution , perhaps easier to follow

while read a;
do
while read b;
do
echo "$b...

Another solution with awk,

$ cat tmp
0x000000 0x5a80 0x0060 BRA.l 0x60 ;file:UserCall.s ;function:_user_call_table ;C_sourceLine:24
0x000002 0x1bc5 RETI ;file:UserCall.s...

I wont be able to help in perl, maybe this will help

awk -F"=" '{print $1}' dictionary_file | sort | uniq -c | awk '{print $2 >> "numrepeats_"$1"_list"}'



This will spit out as many files...