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can anybody tell me why this code does not work?



cat x1.ksh

#!/bin/ksh
set -x
echo "|$#|"
while [ $# -gt 0 ]
do
case $1 in
--+([kK])
shift
K=$1
...

You need a space between the variable and the bracket

Invoke sqlplus and play with these parameters



set long ...
set longchunksize ...
set linesize ...





Hope this helps

If you have execute permissions on the script you should be able to run it.
It looks like your missing the first "/" in your path.. Try
Directory="/home/users/work/"

You can call your script name anything you like. Ie bla.bla xx ....

Typically the first line in the scirpt is the shabang command, this dictates
what shell you are using.. For the most...

Unix provided a nice utilty called nl (number line) see if that could help
you. If not see if this works for you



cat xx.data

red
hello world
green
blue ribbon winner


cat...

The find command offers a lot options (files more than N days old, size
greater than N, different starting places). Depending what your needs
are you can use this in combination with the rm...

you can cd to the directory you like and do something like this:

find . -type -print

The problem is that find walks down the directories, therefore if you have
a directory in your path you...

If you don't know much about code, I'm not sure how helpful this forum will
be to you.

Having said that, you can play around with this and adjust MINIMUM_LEN
and MAXIMUM_LEN to suit your...

Within in Oracle you can do the following:



column username, format a20 head 'User'
column Now format a20 head "Now"
column Expire_Date format a20 head "Expire Date"
column Days format...

This sounds a lot like home work therefore I will get you started and you
can resarch the rest.

cat /tmp/xx
hello


This command will change the word hello to bye in every occurance
in...

The problem is you are testing with -eq which denotes a number.

This works in ksh.

#!/bin/ksh

func1()
{
var="574E47303030303030303030303030303030303135313937"
echo "$var"
}
...

Never been a big fan of getopt in KSH, its very limited. What happens if
you have an option that you want to use the same letter for?

For example, db_id and db_password. You can't use -d for...

#!/bin/ksh
curdir=`pwd`
n20=$curdir/n20
msat=$curdir/n20/msat
if [ ! -d "$n20" ]
then
mkdir "$n20"
fi
if [ ! -d $msat ]
then
mkdir $msat
if [ $? -ne -0 ]
then
echo...