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The shell field/word splitting occurs only on expansion.

From the manual pages of bash:


So:

4.1.10(4)-release$ IFS=+
4.1.10(4)-release$ a=( one+two )
4.1.10(4)-release$ echo "${a[0]}"...

$ nawk -F"[= ]" ' {if($1~/port/) {$6="\$"$1; print $0} else {print $0}} ' test
port1 $PORT && if [ $port1 -eq "$NUM"]; then ........

That's an interesting request. It's hard to know your PID in advance!

But not impossible: The exec command can be used to replace your shell's PID with a command. The process being executed...

Indeed -r is GNU only ....

+ is not part of basic regular expressions. You would have to do something like this:
echo "a b c" | sed 's/ \{1,\}/ \& /g'
or this:
echo "a b c" |...

I'm not sure what you're trying to do with \s. Is that Perl syntax? It's not in POSIX regular expressions.

Remember that the 's/this/that/' syntax replaces the text it matches. It doesn't put...

sed "s/ *[^ ]*/&_label/" file

$ ruby -ane '$F[1]=$F[1]+"_label";puts $F.join(" ")' file
$ awk '{$2=$2"_label"}1' file

paste is expecting filename and not the contents of a file. You can use awk command and remove any lines which dont have "a" and then use paste command

$ cat file1
a 12
b 1
a 3
$ cat file2...

awk -F: '$4="\""$4"\""' OFS=: infile
sed 's/\([^:]*\)/"\1"/4' infile
sed 's/:/&"/3;s/:/"&/4' infile

---------- Post updated at 12:58 ---------- Previous update was at 12:38 ----------

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