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There was a typo in my previous comment, you need to add option -n (for numeric sort)

Cheers ;)

$ awk -F'[- ]' '{print $1, $3}' a
ID_090 2
ID_3787 4
ID_0098 1
ID_12 4

$ awk -F: 'sub(FS $NF,z)' file
Jun 13 12:59
Jun 13 13:02
Jun 13 13:14

Not pretty, but should fit your request
awk '/\"\.\"/{print>"dot.txt"};/\"=\"/{print>"equal.txt"};/\"j\"/{print>"jack.txt"};!/\"[\.=j]\"/{print>"remaining.txt"}' inputfile

awk -F\" '/^ *=/{print $2}' RS=LENGTH file

Try this to print filename and line containing string "Version"
find . -name example.xml -exec awk '/Version/{print FILENAME,$0}' {} \;

$ grep -o -f reference_data.txt input_data.txt | sort | uniq -c
1 CC
2 GHTAS
3 N
1 QER

awk -F"character|numeric" '{print $1}' file

If you just want to count the number of occurences try this:
$ awk '/poc=4060.*loc=JPN$/{++c}END{print c}' file

or
$ cat pattern.txt
poc=4060.*loc=JPN

$ grep -c -f pattern.txt file

paste file1 file2

ESCAPE
:
1,$s/\(^a.*,$\)/\1x

echo -e "service started successfully\n" > log

awk -F"-" '/^Chr[0-9[X]/{print $1":"$2-10"-"$2+10}' file

Try:
perl -lne 'print/(fkafal)/'

or

sed -n 's/.*\(fkafal\).*/\1/p'

Try:
awk '/ORA/&&!/ORA-00001/' file

awk -F/ 'NF>2{print $1,$NF}' file

Have you tried PuTTYgen and Pageant? :)

http://www.chiark.greenend.org.uk/~sgtatham/putty/download.html (http://www.chiark.greenend.org.uk/%7Esgtatham/putty/download.html)

awk -F\| '$1=NR' OFS=\| file

I didn't read the part saying "..files created..." sorry.

I don't know how to do it and according to the UNIX FAQ, it is not possible to see the file creation time.

Files have a last-modified...

awk -v v1=`cat file_b` '{print substr($1,v1,1)}' file_a

$ sed 's/\(.*\)\(\".*\"\)\(.*\)\(\".*\"\)/\2 \4/g;s/\"//g' file
test test2 demo demo2

For the trailer record:
$ awk '{s+=$3}END{print "trailer record, "s}' infile
trailer record, 250

$ DATE=20101018121445
$ DATE2=`echo $DATE | cut -c1-8`
$ echo $DATE2
20101018

unzip -l AMT1-NA-20101007-1.zip | awk '/[0-9]:[0-9]/ {print $4,$1}'