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doing exactly as described:

#!/bin/ksh
if [ ! -f /data/source/a.txt ] ; then
sleep 1800 # wait 30 minutes
fi
[ -f /data/source/a.txt ] && echo 'a.txt found' || echo 'a.txt not found'...

Hi ,
Try this..

#!/usr/bin/ksh
while [ 1 ]
do
if [ -f /data/source/a.txt ]
then
echo " File found"
exit 0
else
sleep 30 # sleeps for 30 seconds
echo "not found "
fi
done

code...

I think you are excepting this one..
while true
do
[ -f /home/oracle/test.txt ] && break
sleep 2
done
ls -l /home/oracle/test.txt

Dates are a pain. I called the file inc.pl, so this is output. use the inc_date function

$ ./inc.pl 1999-12-31
2000-01-01
jim@jim-HP ~
$ ./inc.pl 2011-12-31
2012-01-01
jim@jim-HP ~
$...

With "doubt" you mean "question", right? Bala could have put the 1 inside the single quotes, which is usually done, it does not matter. Everything in awk has the form condition{action}. If the...

That '1' at the end refers to print line.

See these examples to get a clearer picture:

$ cat input
earth
hello
world
mars
$
$ ### If line contains "hello", replace "ll" with "LL" and...

Doh... :D
Aks, in printf formatting %-1000s means left align the argument in a field that is 1000 characters wide (If the field is wider than the argument pad with spaces).

Ha, ha, ha :D Scrutinizer, akshay01987 has shortened my alias name to 'bala'.

@akshay01987: '-' tells printf to pad spaces after the string. So, "%-10s" would print "hello" as "hello<5-spaces>". A...

Try:
awk '/^500/{$0=sprintf("%-"w"s", $0)}1' w=1000
What is bala ?

Something like this?

awk '/^500/ {printf "%-100s", $0}'1 inputfile

Hi.

Something like:

$ date '+%m %Y' | awk '{printf "%02d.01.%d\n", ($1-B>0)?$1:12-B+$1, ($1-B>0)?$2:$2-1}' B=8
06.01.2011

Hi.

That's not the output I'd expect from a non-GNUish date, but anyhoo.

Here's a quick awk one to get you started:
(B is the number of months in the past)


$ date '+%m %Y' | awk -v B=3...

Hi you can do this
if grep -q '^M' file; then
echo "This is a DOS file"
fi
note: you cannot copy-paste this command. The ^M is one character, entered like this on the command line CTRL-V...

/^FL1/|if the scanned line begins with FL1...
{x=$0|store the line in variable x
f?RS:z|if f is true (f is not empty AND f is not equal to 0) then take the value of the Record Separator, whose...

nawk '/^FL1/{x=$0;printf (f?RS:z) x;f++}/^LEX/{print (f?z:x) $0;f=z}' yourfile

Hi akshay01987,

One way:

$ cat infile
FL1ABC
LEX123
FL1DDD
LEX888
LEXTHE
FL1EEE
FL1FFF
LEX555
$ cat script.awk
## When line begins with 'FL1' ...
$0 ~ /^FL1/ {
## If...