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awk '{gsub(/\\|\$/,"#");if($2 in a){}else{a[$2]=i++;}gsub($2,a[$2])}1' infile

53600.88 0 129048320 16 0
53601.96 0 100679424 8 0
53602.16 1 14080 1 0
53603.97 2 95010560 128 0
53614.06 0...

awk '{x[$0]++}END{for(i in x) print i,x[i]}' array.txt

sort yourfile | uniq


Is this what you want?

--ahamed

Try this,
sort -nk2 -nk1 testfile.txt | awk '{if($2 in a){diff=diff+$1-a[$2];a[$2]=$1;i++;b=$2;next}
else {
if(i>0) {--i;if(i==0){printf "%s %f\n",b,0}else{printf "%s %f\n",b,diff/i;}}...

Well, it sounds like you should not try to do too much at once! You have a sector start and length, so convert to sector range first last, and then to page range first last, and then iterate the...

Hi jontjioe,

Another with awk:
awk '{nr=NR%2?(NR-1)/2+1:NR/2;a[NR]=$1}END{print a[nr]}' file1

Regards.

Try this.

awk '{arr[NR]=$1} END{if(NR%2==0)print arr[NR/2]; else print arr[(NR-1)/2]}' inputfile

Yes the awk script requires the same file to be passed into it twice, first pass it to get total records 2nd prints the line.

Shame both your demo files produce the same output:
$ awk...

Ruby(1.9+)

$ ruby -0777 -ne 's=$_.split("\n"); puts (s.size%2==0)? s[(s.size/2)-1]:s[s.size/2] ' file

try:
awk '{a[$2]}$NF=="0"{++b[$2]}END{for(i in a) print i,b[i]?b[i]:"0"|"sort -n"}' file

Try:
awk 'NR==FNR{a[$1]++;next}
{$1=a[$1]?$1 FS a[$1]:$1 FS "0"}
1' filename2 filename1 > newfile

Or shell:
while read fdate rest; do
echo $(date -j -f "%d/%b/%Y:%T" $fdate +%s) "$rest"
done < myfile

You need a bit more code to make it work with awk :).

Anyway, I would use Perl:

perl -MTime::Local -lane'BEGIN {
$month{$_} = ++ $c
for "JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC" =~ /.../g...

Hi

awk 'NR==FNR{a[$2]=$1;next;}{if ($3 in a) print a[$3], $0;}' file1 file2


Guru.