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If your flavor of Unix supports uniq with -D option, this should meet your requirement of listing all duplicate file names ignoring the first 26 characters.

ls | sort -t'.' -k8,9 | uniq -s 26 -D

boaz733,
See this link on several different solutions for printing lines between 2 strings:
...

Using sort:

sort -m -u -k 2,6
1 20 30 40 50 60 6
4 30 40 50 60 70 8

How about including your code so we can review and help you out?

Try using a FOR loop:
FOR %i IN (sec*.txt) DO find %i /c /v ""

find . -type d
Searches for directories recursively starting from current folder.

\( -name archive -o -name log \) -prune
If directory is named archive or log then remove (prune) it from...

Take a look at -l option in grep.

For example:
grep -l keyword $DIRECTORY/*.log

MadeInGermany,
Thanks for the tip, however, based on the requirement, the check to see if the variable exists in the array needs to be negated:

nawk 'FNR==NR{map[$1];next} !($18 in map)'...

Good, you're welcome. But have you looked at identifying these records (or the next ones that you might load) that failed at insert time? Or perhaps this was a one time load and not something you...

Try sometrhing like this:

$nawk 'FNR==NR{map[$1]=$0;next} !map[$18]' import.txt all.txt
1 1 20152005 630 admin NULL NULL NULL NULL NULL NULL ...

How about removing the hour?

awk -F'|' 'NR>2 {array[$1] += $3 count[$1]++ } END { for (a in array) {print a, array[a]/count[a] } } '

See #4 on below link:

Front Panel Controls and Indicators on Sun SPARC Enterprise T5140 Servers - Sun SPARC Enterprise T5140 and T5240 Servers Topic Set...

I understand the concatenation but what I'm not getting is why the extra digits being added are off by one for each line. For example, for line 3, I would expect the extra digit in red to be 1...

Don,
Yes, I added another test record with 3/3/2015 date to test the break logic and forgot to remove it from posted output (as OP did not include it in his file). I missed the semi-colon although...

A quick search of this forum should help you solve your requirement. See this one example using awk:

https://www.unix.com/shell-programming-and-scripting/218015-avg-using-awk.html

kmanivan82,
To use RudiC's 2nd suggestion, try:
awk '{print $1".tmp"}' file_list.txt | xargs -n8 echo rm -f* remove echo once you have tested.

RudiC,
It doesn't appear your 1st suggestion will...

Absolutely! I enjoy reading the posts that peek my interests, chiming in when I can offer a solution and learning from all the variations (there is always more than one way to do something). For...

You can also add comma delimiters between columns and write to csv file. Then open csv file in Excel. Note you will need to choose another delimiter if the data could have embedded commas. Here is an...

You should post the code you have tried so we can see what you are doing wrong.

This will do what you have described.

mv `date +"%Y%m%d"` sommelier

Here is one way:

echo 'a,blank,12,24' | awk -F, '{print $0 "," $3+$4}'
a,blank,12,24,36

nanz143,
If you are using Autosys, why don't you use a calendar definition to run the script only on Sundays?

nanz143, if you have the Autosys job defined to only run on Sunday's at a set time(s), then it will only run on Sunday's. If you are worried about the possibility that someone could manually force...

Try sed with “i” command to insert a line before match for your request to add only one line.

$ cat file.txt
1
2
3
4
5
$ sed "4 i\Inserted new line" file.txt
1
2
3
Inserted new line
4...

Here is an awk solution. Note that the 3rd record in your output file does not match your input and requirement as the fields do not match. Assuming that the '&' in the beginning of field 1 is not...

Another way:

sort -k6,6 -k12,12nr filename | awk '!line[$6]++'