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Try this:

awk '{print "date -d \x27" $3, $4 "\x27 +\x22%s" OFS $9 "\x22"}' file.txt | sh

or this

awk '{system("date -d \x27" $3 " " $4 "\x27 +\x22%s " $9 "\x22")}' file.txt

Or if you...

Try
awk '{print "wget http://example/data/$( date -d \42 " $1 " \42 +\42%Y.%j\42." $2 ")"}' file.txt | sh

Did you try to separate the two command by a semicolon?

The following seems to do what you want, but since your output format is not consistent (no date before first output group, inconsistent spacing), I'm not sure if this is what you want:
awk '
!head...

With a recent shell, this might work:while { read -n4 A; read -n2 B; read -n2 C; read -n2 D; read -n2 E; read REST; }; do echo $A $B $C $D $E; done < file
2012 01 13 24 35
2012 02 14 12 10
2013 04...

It looks like Aia guessed correctly by ignoring the last dollar-sign in your original post:
curl -L http://webpage/${yr}/${mo}/track${yr}${mo}${da}${ho}${mi}$_infos.html
When the shell processes...

What Aia suggested is fine if you're using a system where /bin/sh is not a pure Bourne shell (as it is on Solaris systems) or a 1988 Korn shell (as it is on many AIX systems). But, in addition to...

yr=`awk '{$1=substr($1, 6, 2)}1' file1`

yr will not hold just one year, but every year for each line in file1. The same for each of your variables mo, da, ho and mi. Nonetheless, the characters...

Hello phaethon,

Following may help you in same, considering that 1st field will always have string name in it. Please do let us know if you have more conditions too to get your output.

awk...

awk 'NR==FNR{A[$1];next}!($1 in A)&&$1!=10{M[$1]}END{for(k in M) print k}' file1 file2

Another awk approach:-
awk '$1==10{split("",A);next}++A[$1]>1' file

slight modification to Yoda's approach to not print duplicates for each set in the output
awk '$1==10{split("",A);next}++A[$1]==2' file

Hello phaethon,

Following may also help you in same.

awk 'FNR==NR{A[$1 OFS $2]=$3;next} ($1 OFS $2 in A){$9=A[$1 OFS $2];print} !($1 OFS $2 in A){$9="NA";print}' file2 file1


Output will...

What have you tried?

There are lots of threads with similar problem statements listed at the bottom of the page for this discussion. Did you look at any of them? Can't you adapt the suggestions...

Try this instead:
awk '
FNR == NR {
k[$1, $2] = $3
next
}
{ $9 = (($1, $2) in k) ? k[$1, $2] : "NA"
}
1' file2 file1
With your sample input, this produces the output:
110103 0802 1.16 38...

Hello Senhia83/Phaethon,

Yes script looks to work same as requested, but it is always good practice to mention the complete path in spite of relative path. Otherwise we need to put the script a...

In your old directory (dir1)

mkdir ../newdir

for file in *
do
awk '$20<40' $file > ../newdir/$file
done


Note that newdir will be same level as your olddir

Will GAP number and RMS num ever be in the same line?
or is the test to be for their one time occurance in the whole file?

Maybe this will help, could be done more elegantly of course..


for file in *
do
gap=$( awk '/Gap/' "$file" | sed -e 's/.*Gap//;' | awk '{print $1}' );
rms=$( awk '/RMS/' "$file" | sed...

In addition to what ongoto and RavinderSingh13 asked, Is RMS also always in a fixed column?

Hello phaethon,

You should us some input and more details like is RMS and GAP will be on same line. After making an assumption like you have
RMS as 12th field only and is on a different line...

Use printf "%s",string instead of print string!

With all the irregularities of spaces and commas between your meaningful fields, it might be best to use awk versatile field separator definition. Try:awk '$1=="nmm" {gsub...

Got Perl?

perl -00 -wne '@values = $_ =~ /(\d+\.?\d+)/g and print "@values\n"' file.txt

A quick alternative is to run your script through:
| paste -d " " - - -