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Hello r_t_1601,

Could you please try following and let me know if this helps you.

awk -v STR1='/scripts/waitForDummyFilePDS.sh -f$Paramdummyfile -H$ParamIP -e$Paramemail -j$Paramprefilename' ...

Try
awk -v RPST="$STR1|$STR2" 'BEGIN {n = split (RPST, RP, "|")} /VALUEPAIR EXECORDER/ {T=$NF; sub (/""/, "\"" RP[++CNT] "\"", T); sub ($NF, T)} 1' filebut make sure the strings STR1 & 2 have...

Hello r_t_1601,

Not sure how you want to substitute the string VALUE with multiple strings as it is present in many places, following is the example of using one variable and doing substitution...

Any attempts/ideas/thoughts from your side?

---------- Post updated at 11:33 ---------- Previous update was at 11:11 ----------

Howsoever, tryawk '{print $0 ORS > "file" 2- ($2 ~ /dn:...

grep can't do substitutions; sed or awk (amongst others) can. Actually, you don't need grep at all. Try awk '
FNR==NR {R[$1".log"]=$2
next
}

$2 in R ...

GNU/Linux is rather vague.
When asked about OS/shell, please post the output of these:
uname -a
$SHELL --version

Hope i understood you right, if so, you could try:
(Note: i've just reused your...

If you have a process that been running a few days you may end up with "Jan23" in the ps coloumn 5 or even "2014" if its been running a few months.

This solution may prove to be a little more...

How about ps -eaf | awk -vBEF=$(( $(date +"(%H * 60) + %M") - 15)) ' /pmdtm/ {split($5,a,":"); if (((a[1]*60)+a[2]) < BEF) print "pmstack -p ", $2}'
pmstack -p 2026
pmstack -p 2100
pmstack -p ...

Try:
awk -F, '!($1=="UPDATE PLAN ADD RATE SCHEDULE" && $4=="") && !($1=="CREATE L2 SUPP PLAN" && $5=="")' Source_File.csv

Scrutinizer here is two see

Sample output | Unix Linux Forums | Shell Programming and Scripting (https://www.unix.com/shell-programming-scripting/243300-sample-output.html)

Urgent ! | Unix Linux...