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Im sure there are better ways to do it but the following will work assuming that the amount of comma separated values in $10 and $11 are the same:

awk -F '\t'...

What about this?

awk -F '\t' '{split($10,s1,",");split($11,s2,","); print $9,$13,$2,s1[1]"-"s2[1],s1[2]"-"s2[2]}' file

Output:

2 ACKR1 NM_002036.3 159173802-159174770 159175250-159176290

Sed alternative

sed -n 's/.*\[\([0-9]\{23\}\)\].*/\1/p' filename

Hi, regarding code :

awk '{gsub("\n[^\n]*/",","); sub(",","\n")}1' RS= ORS='\n\n' file

Would you be able to explain how this works as i cant understand it?

Many thanks

Hi Mo, the desired output you have put does not match what you have specified, as
Parent=tRNA-Tyr6.r01 has a + in file1 but your desired output shows a -
Also you have put the last field from...

If you did want the last field from file2 you could do the following:



awk 'NR==FNR{a[$1]=$2;next} $10 in a {print $10, a[$10],$7}' file2 file1

This would give output as


...

Not sure if your specifications requires the quotations or not but what about:

awk '{print "\""$6,$7,$8"\"","\""substr($9,1,length($9)-4)"\""}' filename

Will produce:

"Jun 03 16:32"...

ps -ef | grep abc.sh | grep -v grep

If there is an entry then the job is still running

If there isnt then the job has completed