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ext_sta=`sqlplus -s ${Connstr} <<eof
set heading off;
set pagesize 0;
set feedback off;
set serveroutput on;
execute EDW_MEM_KEY_UPDATE ;
quit;
eof`

This code was posted here by someone else to determine yesterday:
#!/usr/bin/ksh
date '+%m %d %Y' |
{
read MONTH DAY YEAR
DAY=`expr "$DAY" - 1`
case "$DAY" in
0)
...

Amit,
You can also try with below code
But this will search the 3rdjuly.txt for each line of the 4thjuly.txt

For eg :
Even if the 4thjuly.txt line 2 and 3rdjuly.txt line 2 are not same but...

Amit,
Please check below.I have take the input 3rdjuly.txt and 4thjuly.txt
as per the your very first post
The results are same as you are expecting

Input:

cat 3rdjuly.txt...

That will suppress duplicate records within 4. This could be a problem if one of the new lines in 4 is identical to an older line in 3 and 4.

awk '!($0 in a){a[$0];if(FILENAME=="4")print}' 3 4 > new

Krishna,
One important thing to remember is the difference between
single ">" (creates a new file) and double ">>" (creates the file
if it does not exists, if it exists, appends to it).

Use the [:cntrl:] character class with any tool that supports regular expressions.

Regards,
Alister

Try this Insert ^M by using ^v and ^M

perl -0ne 'print "Control Chars found in $ARGV" if /^M/g' txt.txt

You can do something like that :
extract_date=$( echo ${file_name} | \
nawk -F '[_.\-]' '
/^mireport/ { printf "%s-%s-%s", substr($2,5,2), substr($2,7,2),...