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Don't see LINUX or LVM in the output of fdisk -l. Maybe you are using other than GNU Linux?

What I see here...
NewDisk=`fdisk -l | grep Linux | egrep -v '\*|LVM' |awk '{print $1}' | sed...

If you're doing grep | sed | grep -v | awk | sed | cut | kitchen | sink, just use awk and be done with it.

fdisk prints 'Linux' on my system, not LINUX, but adjust to taste.

$ fdisk -l | awk...

In sed you can replace the slash of the substitute command with almost any character .
$ echo "Turn forward // into dashes" | sed 's/\//-/g'
Turn forward -- into dashes

Using | instead of / :...

Just put the code in one line!
awk 'NF{if($0~/Six/){H=$0;sub(/Six:[ \t]*/,X,H)}else{gsub("\t",X,$0);S=S?S OFS $0:$0}next}!NF{print H,S;S=""}END{print H,S}' OFS=, file

Tryawk '{gsub("[\t ]*","");$1=$6"\t"$1; sub (/^[^:]*:/,"",$1); $6=""}1' RS= ORS="\n" FS="\n" OFS="," file

Try:
sed 's/^\(...\) \(...\) \([0-9][0-9]\).*2011/\2 \3 2011/' INPUTFILE
It works only for 2011 year but it's easy enough to fix this.

PS And you should'n have other "2011" in your strings.

You can use also builtin calculation, tested using ksh and bash

echo $(( 10+RANDOM%21 ))
# or more generic
min=10
max=30
((diff=max-min+1))
echo $(( min + RANDOM%diff ))

Hi,

Using 'perl':

$ perl -pe 's/\s*,\s*/,/g' infile
Sat Jul 23 16:10:03 EDT 2011,12345678,PROD,xyz_2345677,testuuyt,149693,abtryu
Jul 22 2011,NULL,PROD,yt12345,testuuytoy,162469,abtryu
Jul...

Through Sed..
sed 's/ *, */,/g' inputfile

echo "10+$RANDOM%10*(2)+2 " | bc

will generate random numbers in 12~30 range, if that suffice.

Oh God,

You changed the order!!!

try


MM="Jul"
DD=20
nawk -v d=$DD -v m=$MM '$2==m && $3==d' input_file

awk -F# '{gsub(".","x",$NF)}1' OFS=# file

This command should do the job:
awk '/--/;/\/\*/{p=1};p;/\*\//{p=0}' file
This is the output I get:
$ cat file
Tue Mar 25 23:35:00 GMT 2008
-- COMMENT Tue Mar 25 21:34:23 GMT 2008
Tue Mar 25...

This should do it.


awk -F'--' '{print $1}' $ORACLE_CODE_FILENAME
removing blank lines is left as an exercise for the reader ;)

Oh my... ok, let me give it a shot:

#!/bin/ksh
#%W% %I% %D% %T% ---- these are comments (starting with #)
#%W%G --- they don't do anything

The beginning of this line here://g'
Seems like...

You can use od to show the last characacter of a file.
$ echo -n hello > testfile1
$ echo hello > testfile2
$ file=testfile1
$ od -An -tc -j $(( $(ls -l $file | awk '{print $5}') - 1 )) $file
...