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Use backslashes ..

$ ssh user@servername "a=\$(hostname); echo \$a"
servername
$

use nawk instead of awk

can you post the command you tried.

try this.


h=$(hostname);df -k | awk -v h="$h" '!/dcs/ && NR>1 {if(substr($5,0,length($5)-1)>87)print h" "$5" " $6}' >> sms.txt

Yes.

find .. -type d -mtime +1 | while read d; do
[ -z "`ls "$d"`" ] && echo rmdir "$d"
done

Try and if it works remove "echo".

PS It is unclear what it means - "1 day old" for directories....

On my Linux box, it doesnt work on either sh nor bash:

$ ls file*
file1 file2 file3 filelist
$ cat testf.sh
#!/bin/sh
if [ -f file* ] ; then
echo exist multiple
fi
$ ./testf.sh
[:...

ok, try this..

$? is a special variable which tells, the previous command is success or not.

if it holds 0, then it success.


ls -l /a/b/c/d/e/K*-*-*-*.s > /dev/null
if [ "$?" -eq "0"...